All categories

3 years ago

Is it possible that the image of a point after a reflection could be the same point as the preimage?

1 answer:

3 0

Yes, it is possible. For example, let's say that point A is (0,4) and there's a reflection over the y-axis, then point A would still be (0,4).

You might be interested in

Answer pleaseee!!!!!!!

stiks02 [169]

3 x 1/8 bottom left. The third one

4 0

3 years ago

Pls help me I will give brainlyiest

storchak [24]

Answer:

57.72 in^2

Step-by-step explanation:

Question 1. Shapes are triangle, semi-circle, and rectangle.

Question 2.Find area of rectangle first. Then area of triangle and circle. Subtract area of triangle and circle. Then add the difference with the rectangles area.

Question 3.

Rectangle's area:48 in^2

Triangles area:8*4/2= 16 in^2

Circle Area: pi*r^2/2(since its a semi-circle)

3.14*2^2=3.14*4=12.56/2=6.28 in^2

Question 4.

16-6.28=9.72

9.72+48=57.72 in^2

5 0

2 years ago

A point P moves such that it is three units from the point (3, 4). Obtain the

Softa [21]

The right answer is y=-3

4 0

3 years ago

Read 2 more answers

Select all the ordered pairs that are in the solution set for the inequality graphed below.

shtirl [24]

Idk I really did not study this since I’m in AP

7 0

3 years ago

Read 2 more answers

Y/2 - (-1.12) = 3.12

ahrayia [7]

$\fbox{y=4}$

$\frac{y}{2} -(-1.12)=3.12$

Simplify:

$\frac{1}{2} y+1.12=3.12$

Subtract 1.12 on both sides:

$\frac{1}{2} y+1.12-1.12=3.12-1.12$

$\frac{1}{2} y=12$

Multiply both sides by 2:

$2\times(\frac{1}{2} y)(2)\times(2)$

$y=4$

4 0

1 year ago