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creativ13 [48]
4 years ago
13

Solve. 3^x = 81 a X= 2 b. X= 4 c. x=6 d. x =9 HELPPPPP

Mathematics
2 answers:
OverLord2011 [107]4 years ago
4 0

Answer:

it's B on ed

Step-by-step explanation:

100%

maw [93]4 years ago
3 0

Answer:

B= x=4

3 x 3 x 3 x 3

3 x 3=9

3 x 3=9

9 x 9=81

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Wittaler [7]

Answer:

This is not correct.

Step-by-step explanation:

10 ml = 0.01 cm³.

Now, to find that is this correct or not.

As, the unit rate is:

1\ ml = 1\ cm^3

Thus, 10\ ml=10\ cm^3.

So, 10\ ml=0.01\ cm^3 is not correct.

Therefore, this is not correct.

5 0
3 years ago
Please solve! 20 points!
zepelin [54]
The volume of figure A is 18 cu ft

Hope this is right for y’a :)
6 0
3 years ago
Makayla was training for a 2k run. it was tiring, and she had to stop and walk to the finish line.if she had run 650 meters out
jonny [76]
She ran 21 inches. Thats your answer. sorry if im wrong
7 0
4 years ago
Read 2 more answers
The quotient of a number and 15 is no greater than 450. What was the possible values for the number??
finlep [7]
\frac{x}{15} \leq 450

Solve for x by cross multiplying 
4 0
3 years ago
Guided Practice
emmasim [6.3K]

Answer:

B.

y=2 · 3xy equals 2 times 3 superscript x baseline

Step-by-step explanation:

The bacteria culture starts with 500 bacteria and doubles size every half hour.= 2 hours

32,000

Thus, after three hours, the population of bacteria is 32,000.= 3 hours

A bacteria culture starts with 500 bacteria and doubles in size every half hour.1

(a) How many bacteria are there after 3 hours?

We are told “. . . doubles in size every half hour.” Let’s make a table of the time and population:

t 0 0.5 1.0 1.5 2.0 2.5 3.0

bacteria 500 1000 2000 4000 8000 16000 32000

Thus, after three hours, the population of bacteria is 32,000.

(b) How many bacteria are there after t hours?

In t hours, there are 2t doubling periods. (For example, after 4 hours, the population has doubled 8

times.) The initial value is 500, so the population P at time t is given by

P(t) = 500 · 2

2t

This is an acceptable response, but in calculus and all advanced mathematics and science, we will

almost always want to use the natural exponential base, e. Let’s redo the problem using the natural

exponential growth function

P(t) = P0e

rt

We are given that the initial population is 500 bacteria. So P0 = 500 and we have

P(t) = 500ert

We know that after 1 hour, there are 2000 bacteria. (We could’ve used any other pair from our table

that we wish.) Substituting into our function, we get

P(t) = 500ert

2000 = 500er·1

2000 = 500er

1

500

· 2000 =

1

500

· 500er

4 = er

and now we use the natural logarithm to solve for r

ln (4) = ln (er

)

ln (4) = r · ln (e)

ln (4) = r

1.3863 ≈ r

Thus the function P(t) = 500e1.3863t gives the number of bacteria after t hours.

(c) How many bacteria are there after 40 minutes?

The input t to our function is given in hours, so we must convert 40 minutes into hours. So (40 min)

1 hr

60 min

=

2

3

hr.

P(t) = 500e1.3863t

P

2

3

= 500e1.3863·(2/3)

P

2

3

≈ 1259.9258

Thus, after 40 minutes (2/3 of an hour), there are about 1260 bacteria.

(d) Graph the population function and estimate the time for the population to reach 100,000.

50000

100000

1 2 3 4 5

b

(3.8219, 100,000)

t

P

Using the calc:intersect on the TI-84, we get the point (3.8219, 100000), thus the population will

reach 100,000 in about 3.82 yrs

6 0
3 years ago
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