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ozzi
3 years ago
9

How many gramsare in 3.0 moles of KCI(potassium chloride)?​

Chemistry
1 answer:
Ganezh [65]3 years ago
7 0

Answer: I thinc 223.6539

Explanation:

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What happens to a reducing agent during a redox reaction?
Nuetrik [128]
Reducing agent is an compound/atom, that loses an electron and is oxidized.

0.........+I.............+II............0
Ca + 2HCl ----> CaCl₂ + H₂

Calcium is oxidized --- it's reducing agent (reductant).
Hydrogen is reduced --- HCl is oxidizing agent.
7 0
2 years ago
Which describes the polarity in a water molecule?
PilotLPTM [1.2K]
<span>Water is considered as a polar molecule because its electrons has an uneven distribution. It has a partial negative charge and a partial positive charge on both ends of the molecule. </span>I hope my answer has come to your help. God bless and have a nice day ahead!
7 0
3 years ago
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HELP PLEASE!
tia_tia [17]

Vocabulary. Balanced chemical equation: A chemical equation in which the number of each type of atom is equal on the two sides of the equation.

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5 0
3 years ago
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Calculate ∆G ◦ r for the decomposition of mercury(II) oxide 2 HgO(s) → 2 Hg(ℓ) + O2(g) ∆H◦ f −90.83 − − (kJ · mol−1 ) ∆S ◦ m 70.
bagirrra123 [75]

Answer:

4. +117,1 kJ/mol

Explanation:

ΔG of a reaction is:

ΔGr = ΔHr - TΔSr <em>(1)</em>

For the reaction:

2 HgO(s) → 2 Hg(l) + O₂(g)

ΔHr: 2ΔHf Hg(l) + ΔHf O₂(g) - 2ΔHf HgO(s)

As ΔHf of Hg(l) and ΔHf O₂(g) are 0:

ΔHr: - 2ΔHf HgO(s) = <u><em>181,66 kJ/mol</em></u>

<u><em /></u>

In the same way ΔSr is:

ΔSr= 2ΔS° Hg(l) + ΔS° O₂(g) - 2ΔS° HgO(s)

ΔSr= 2* 76,02J/Kmol + 205,14 J/Kmol - 2*70,19 J/Kmol

ΔSr= 216,8 J/Kmol = <em><u>0,216 kJ/Kmol</u></em>

Thus, ΔGr at 298K is:

ΔGr = 181,66 kJ/mol - 298K*0,216kJ/Kmol

ΔGr = +117,3 kJ/mol ≈ <em>4. +117,1 kJ/mol</em>

<em></em>

I hope it helps!

5 0
3 years ago
How many atoms of phosphorus are in 3.80 mol of copper(II) phosphate?
Sladkaya [172]
Wouldn't you take Avogadro' number and multiply by 3.80 maybe
6 0
3 years ago
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