When a metal reacts with a salt, it displaces the metal present in the salt only if the metal has higher relative reactivity.
in this case , the displacing metal is same as the metal present in salt. both (being same metal)have same relative reactivity. hence, no displacement . NO reaction.
Answer:
3.6 x 4.639 + 5.831 = 2000
Explanation:
In this problem, we need to find the value of 3.6 x 4.639 + 5.831.
Here, 3.6 has 2, 4.639 and 5.831 has 4 significant figures.
We can use BODMAS RULE to find it as follows :
3.6 x 4.639 + 5.831 = (3.6 x 4.639) + 5.831
= 2325.96 + 5.831
in significant gigure,
= 2300 + 5.831
= 2305.831
In one significant figure,
= 2000
Hence, the answer of the problem is 2000.
Answer:
Explanation:
OK this is simple
i'll try to do the unanswered question
CaCl2
In the table
You look for calcium,Ca you fill 1
THen for Chloride=2
i hope you've understood
Answer:
Mass = 7.2 g
Explanation:
Given data:
Mass of water produced = ?
Mass of oxygen = 7.8 g
Solution:
Chemical equation:
2H₂ + O₂ → 2H₂O
Number of moles of oxygen:
Number of moles = mass/ molar mass
Number of moles = 7.8 g/ 32 g/mol
Number of moles = 0.2 mol
Now we will compare the moles of water with oxygen.
O₂ : H₂O
1 : 2
0.2 : 2×0.2 = 0.4 mol
Mass of water:
Mass = number of moles × number of moles
Mass = 0.4 mol × 18 g/mol
Mass = 7.2 g
Answer:
The density of O₂ gas is 1.71 
Explanation:
Density is a quantity that allows you to measure the amount of mass in a given volume of a substance. So density is defined as the quotient between the mass of a body and the volume it occupies:
An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:
P * V = n * R * T
So, you can get:
The relationship between number of moles and mass is:
Replacing:
So:
Knowing that 1 mol of O has 16 g, the molar mass of O₂ gas is 32 
.
Then:
In this case you know:
- P=1.27 atm
- molar mass of O₂= 32 .
- R= 0.0821
- T= 16 °C= 289 °K (0°C= 273°K)
Replacing:
Solving:
density= 1.71
<u><em>The density of O₂ gas is 1.71 </em></u><u><em></em></u>
