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Leni [432]
3 years ago
15

Gold is a precious substance explain how you would classify gold

Chemistry
1 answer:
vodomira [7]3 years ago
5 0
I would classify gold as an underground treasure, high in value that can be issued with sentimental value.

Or in smaller kid langue...

I would classify gold as an underground metal that can be used on jewelry or to make something that could mean something to someone.

If your in 2-4, I would use the second one. If you are in a grade higher than 4th, go ahead and blow your teachers mind by writing the first one. PLEASE do not copy it word for word! Make it your own so you do not plagiarise!

Plagiarise- "copy from {someone} and pass it off as one's own." (google web)
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The rate of decomposition of N2O5 in CCl4 at 317 K has been studied by monitoring the concentration of N2O5 in the solution. 2 N
pav-90 [236]

Answer:

Average rate of reaction is 0.000565 M/min

Explanation:

Applying law of mass action for the given reaction:

Average rate = -\frac{1}{2}\frac{[N_{2}O_{5}]}{\Delta t}=\frac{1}{4}\frac{\Delta [NO_{2}]}{\Delta t}=\frac{\Delta [O_{2}]}{\Delta t}

Where, -\frac{1}{2}\frac{[N_{2}O_{5}]}{\Delta t} represents average rate of disappearance of N_{2}O_{5}, \frac{1}{4}\frac{[NO_{2}]}{\Delta t} represents average rate of appearance of NO_{2} and \frac{[O_{2}]}{\Delta t} represents average rate of appearance of O_{2}

Here,-\frac{[N_{2}O_{5}]}{\Delta t} = -\frac{(2.16-2.36)}{(177-0)}M/min=0.00113M/min

So average rate of reaction = [tex]-\frac{1}{2}\frac{[N_{2}O_{5}]}{\Delta t}[/tex] = \frac{1}{2}\times (0.00113M/min)=0.000565M/min

7 0
3 years ago
What is starch test?​
Fed [463]

Answer:

The starch test also known as the iodine test is used to test for the presence of starch.

Sorry if this isn’t detailed enough. You can go on google/wikipedia and find much more detail if necessary. ^-^

4 0
3 years ago
Read 2 more answers
Carbon disulfide, CS2, can be made from coke, C(s), and sulfur dioxide, SO2(g). C(s) + SO2(g) à CS2(s) + CO2(g) If the actual yi
Virty [35]

Answer:

450g of coke (C)

Explanation:

Step 1:

The balanced equation for the reaction is given below:

3C(s) + 2SO2(g) —> CS2(s) + 2CO2(g)

Step 2:

Determination of the mass of C that reacted and the mass of CS2 produced from the balanced equation.

This is illustrated below:

Molar Mass of C = 12g/mol

Mass of C from the balanced equation = 3 x 12 = 36g

Molar Mass of CS2 = 12 + (32x2) = 12 + 64 = 76g/mol.

From the balanced equation above, 36g of C reacted to produce 76g of CS2.

Step 3:

Determination of the mass of C required to produce 950g of CS2. This is illustrated below:

From the balanced equation above, 36g of C reacted to produce 76g of CS2.

Therefore, Xg of C will react to produce 950g of CS2 i.e

Xg of C = (36 x 950)/76

Xg of C = 450g

From the calculations made above, 450g of coke (C) is needed to produce 950g of CS2.

6 0
3 years ago
What is the frequency of a light that has a wavelength of 3.0 x 10 -7m?
alexdok [17]

Answer:

 frequency of light (f) = 1 x 10¹⁵s⁻¹

Explanation:

Given Data:

Wavelength of light λ = 3.0 x10⁻⁷m

Frequency of light: to be calculated

Formula Used to find frequency:

                                  f = V/λ ........................... (1)

where

f is the frequency

V is the velocity

λ is wavelength

Velocity of light = 3 x 10⁸ ms⁻¹

put the values in equation (1)

                                     f =  3 x 10⁸ ms⁻¹ / 3.0 x10⁻⁷m

                                     f = 1 x 10¹⁵s⁻¹

   So the frequency of light =  1 x 10¹⁵s⁻¹

7 0
3 years ago
What is the color of phenolphthalein in weak base
vichka [17]

Answer:

Pink

Explanation:

Phenolphthalein is often used as an indicator in acid–base titrations. For this application, it turns colorless in acidic solutions and pink in basic solutions.

hope it helps you and give me a brainliest

4 0
2 years ago
Read 2 more answers
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