The number of mole of copper in the sample is 0.008 mole.
Mole is simply defined as the unit of amount in a substance.
The mole of a substance can be obtained by dividing the mass of the subtance by its molar mass i.e
Mole = mass / molar mass
With the above information, we can obtain the mole of copper in the compound as follow:
Mass of copper = 0.5066 g
Molar mass of copper = 63.5 g/mol
<h3>Mole of copper =? </h3>
Mole = mass / molar mass
Mole of copper = 0.5066 / 63.5
<h3>Mole of copper = 0.008 mole </h3>
Therefore, 0.008 mole of copper was initially present in the compound.
Learn more: brainly.com/question/14295066
Answer:
5 L.
Explanation:
From the question given above, the following data were obtained:
Initial volume (V1) = 10 L
Initial pressure (P1) = 2.5 atm
Final pressure (P2) = 5 atm
Final volume (V2) =.?
Since the temperature is constant, we shall apply the Boyle's law equation to determine the new volume of the gas. This can be obtained as follow:
P1V1 = P2V2
2.5 × 10 = 5 × V2
25 = 5 × V2
Divide both side by 5
V2 =25/5
V2 = 5 L
Thus, the new volume of the gas is 5 L
Answer:
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