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umka21 [38]
3 years ago
6

Magnesium and iron are metallic elements. How does a mole of magnesium compare with a mole of iron?

Chemistry
2 answers:
Alexus [3.1K]3 years ago
6 0
Given a mole each for iron and magnesium, the number of atoms of each element is equal. Iron has a greater mass due to its greater molecular weight. The correct statement among the choices is D.
kari74 [83]3 years ago
5 0

Answer: d) They both have the same number of atoms.

Explanation:

A mole is defined as the amount of substance that contains Avogardro number of the substance. Avogadro's number is given by 6.022\times 10^{23}.

1mole=6.022\times 10^{23}particles

According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass and contains avogadro's number 6.023\times 10^{23}

Thus 1 mole of magnesium and iron both contains 6.023\times 10^{23} particles.

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The chemical combination of two or more different atoms in fixed amounts is called a(n)
valkas [14]
I think the correct answer from the list of choices above is option B. <span>The chemical combination of two or more different atoms in fixed amounts is called a compound. There are two type of compounds namely the ionic and covalent compounds.</span>
4 0
3 years ago
Read 2 more answers
A container is filled with hydrogen gas. It has a volume of 4 liters and a pressure of 2 atm. If the pressure of the container i
Dennis_Churaev [7]

Answer:

1.33 L.

Explanation:

  • We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R  is the general gas constant,

T is the temperature of the gas in K.

  • If n and T are constant, and have different values of P and V:

<em>(P₁V₁) = (P₂V₂)</em>

<em></em>

Knowing that:

V₁  =  4.0 L, P₁ = 2.0 atm,

V₂  =  ??? L, P₂ = 6.0 atm.

  • Applying in the above equation

(P ₁V₁) = (P₂V₂)

<em>∴ V₂ = P ₁V₁/P₂</em> = (2.0 atm)(4.0 L)/(6.0 atm) =<em> 1.33 L.</em>

4 0
3 years ago
This question deals with waste disposal in the Solutions and Spectroscopy experiment. What should be done to waste solutions con
Korvikt [17]

Answer:

b. It should be dumped in a beaker labeled "waste copper" on one's bench during the experiment.

d. It should be disposed of in the bottle for waste copper ion when work is completed.

Explanation:

Solutions containing copper ion should never be disposed of by dumping them in a sink or in common trash cans, because this will cause pollution in rivers, lakes and seas, being a contaminating agent to both human beings and animals. They should be placed in appropriate compatible containers that can be hermetically sealed. The sealed containers must be labeled with the name and class of hazardous substance they contain and the date they were generated.

It never should be returned to the bottle containing the solution, since it can contaminate the solution of the bottle.

In the Solutions and Spectroscopy experiments there is always wastes.

3 0
3 years ago
Hydrogen bonding occurs when hydrogen is bonded to N, O, or F. Which of the following molecules has hydrogen bonding, when bondi
Makovka662 [10]

Answer:

I think the answer is……

O B.H2S

Explanation:

I’m not sure tho, I’m just not 100% positive.

5 0
3 years ago
Boron has an average mass of 10.81. One isotope of boron has a mass of 10.012938 and a relative abundance of 19.80 percent. The
Andrej [43]

The average mass of an atom is calculated with the formula:

average mass = abundance of isotope (1) × mass of isotope (1) + abundance of isotope (2) × mass of isotope (2) + ...  an so on

For the boron we have two isotopes, so the formula will become:

average mass of boron = abundance of isotope (1) × mass of isotope (1) + abundance of isotope (2) × mass of isotope (2)

We plug in the values:

10.81 = 0.1980 × 10.012938  + 0.8020 × mass of isotope (2)

10.81 = 1.98 + 0.8020 × mass of isotope (2)

10.81 - 1.98 = 0.8020 × mass of isotope (2)

8.83 = 0.8020 × mass of isotope (2)

mass of isotope (2) = 8.83 / 0.8020

mass of isotope (2) = 11.009975

mass of isotope (1) = 10.012938 (given by the question)

5 0
3 years ago
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