Given:
In a right angled triangle ABC the perpendicular and the base measure 3 cm.
To find:
The hypotenuse and three trigonometric ratios.
Solution:
Pythagoras theorem:
Use Pythagoras theorem in triangle ABC.
The three trigonometric ratios are
Similarly,
And,
Therefore, the hypotenuse is 
cm and three trigonometric ratios are 
.
Answer:
-58, -57, -56
Step-by-step explanation:
if the first integer is x,
the second integer must be x + 1 (because it's consecutive)
and the third must be x + 2
Therefore:
3 times the sum of the first and third integers is -342:
3 * (x + (x+2) ) = -342
Combine like terms in parentheses
3 * (2x + 2) = -342
Distribute the 3 to the 2x and the 2:
6x + 6 = -342
Subtract 6 on both sides
6x = -348
Divide by 6 on both sides
x = -58
x + 1 = -57
x + 2 = -56
-58, -57, -56
Check:
3 * (-58 + -56) = 3 * -114 = -342
A word phrase for 3m would be: 3 times a number m
Answer: y=-3/2x+3
Step-by-step explanation:
First subtract 3x from both sides to start isolating the y.
Then you get 2y=-3x+6
Divide both sides by 2 to get y alone and you get
y=-3/2x+3
