Answer:
The amount of effective interest expense that chaco will record in the first six months is $14,375
Explanation:
interest payment that will be first made is on June 30, Year 1. Therefore, the outstanding balance used in the calculation is the issue price.
The interest expense is calculated by these formula
Interest expense = Effective semiannual interest rate × Outstanding balance
Interest expense = (8% ÷ 2) × $359,378 = $14,375
So the interest expense is gotten as %14,375
Answer:
50,490 units
Explanation:
The computation of the number of units the company should produced is shown below:
= Expected sales units + ending inventory units - opening inventory units
where,
Opening inventory units is 1,350 units
Expected sales units is
= $27,000 + $27,000 × 60%
= $27,000 + $16,200
= 43,200 units
The ending inventory units is
= $43,200 × 20%
= 8,640 units
So, the units to be produced is
= 43,200 units + 8,640 units - 1,350 units
= 50,490 units
Answer:
I think the answer is "D"
Explanation:
hope it helps :)
Answer:
it take 29.23 years, my salary to double.
Explanation:
To make the salary double I have to increase the value of salary by 100%. If inflation rate is 2.4 percent per year and salary increase the same rate the time period to make it double can be calculated as follow.
As every year 2.4% has compounding effect, so we will use compounding formula to solve this problem.
Target value = Existing value ( 1 + growth rate )^time period
200% = 100% ( 1 + 2.4% )^n
2 = 1 ( 1 + 0.024 )^n
2 = 1 ( 1.024 )^n
2 = 1.024^n
Taking log on both sides to solve the n
Log 2 = n Log 1.024
n = Log 2 / Log 1.024
n = 29.23 years
I will take 29.23 year to double the salary
Answer: hello your question is incomplete attached below is the complete question.
answer :
3.02 million, 2.96 million, 2.91 million
Explanation:
<u>Determine the swap rate over a 3-year period</u>
swap rate = forward exchange rate * exchange amount
For year 1
1.4 * ( 1 + 0.03 / 1 + 0.05 ) * 2.2 million
= 1.4 ( 0.98095 ) * 2.2
= 3.02 million
For year 2
1.4 * ( 1 + 0.03 / 1 + 0.05 )^2 * 2..2 million
= 1.4 ( 0.98095 )^2 * 2.2 million
= 2.96378 million
For year 3
1.4 * ( 1 + 0.03 / 1 + 0.05 )^3 * 2.2 million
= 1.4 ( 0.98095 )^3 * 2.2 million
= 2.90733 million