Answer:
MLH is congruent to JKI
LNK is congruent to HNI
I think that's how you're supposed to answer it...
Answer:

Step-by-step explanation:
Using the Pythagorean identity
sin²x + cos²x = 1, then
sinx = 
Note that (
)² = 
sinΘ = 
=
= 
Answer:
c and d are correct
Step-by-step explanation:
Answer:
a=35x−x^2
Step-by-step explanation:
Having
70 ft of fencing with a
width of x
feet and knowing the perimeter of a rectangle is
p=2w+2l
we can state the length of the garden as:
70=2x+2l
and solving for l
we know the length with be:
2l=70−2x or l=35−x
And then knowing the formula for the area of a rectangle is
a=w⋅l
we can write the equation as:
a=x⋅(35−x)a=35x−x^2