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Crazy boy [7]
3 years ago
15

Please help me with this questions.​

Chemistry
1 answer:
Alisiya [41]3 years ago
7 0
1. Hydrogen
2. 11
3. Alkali metals
4. Increases
5. Increases
7. Seven
8. Less
9. hydrogen
10. Idk
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A 265-mL flask contains pure helium at a pressure of 751 torrs. A second flask with a volume of 465 mL contains pure argon at a
Nadya [2.5K]

Answer:

Total Pressure = 745.6 torr

Partial Pressure of He = 272.8 torr

Partial Pressure of Ar =  472.8 torr

Explanation:

Step 1: Data given

Volume of the flask helium = 265 mL

Pressure in the helium flask = 751 torr = 751/760 atm

Volume of the flask argon = 465 mL

Pressure in the argon flask = 727 torr = 727/760 atm

The total pressure exerted by a gaseous mixture is equal to the sum of the partial pressures of each individual component in a gas mixture.

Step 2: Calculate total volume

Total volume = 265 mL + 465 mL = 730 mL =  0.730 L

Step 3: Boyle's Law:

P1V1=P2V2

⇒ with P1 = total pressure gas exerts in its own flask

 ⇒ with V1 = volume of flask with stopcock valve closed

 ⇒ with P2 = partial pressure of gas exerts on total volume of both flasks when stopcock valve is opened  

 ⇒ with V2 = total volume of both flasks with stopcock valve opened

Helium using Boyle's Law equation from above:

P1V1=P2V2

⇒ with P1 = Pressure of helium = 751 /760 = 0.98816 atm

 ⇒ with V1 = volume of helium = 0.265 L

 ⇒ with P2 = The new partial pressure of helium

 ⇒ with V2 = total volume = 0.730 L

(0.98816 atm)(0.265L)=P2(0.730L)

P2=0.359 atm

Argon using Boyle's Law equation from above:

P1V1=P2V2

⇒ with P1 = Pressure of argon = 727/760 = 0.95658 atm

 ⇒ with V1 = volume of argon = 0.465 L

 ⇒ with P2 = The new partial pressure of argon

 ⇒ with V2 = total volume = 0.730 L

(0.95658 atm)(0.465L)=P2(0.730L)

P2=0.609 atm

Step 4: Convert pressure in atm to torr

Pressure helium = 0.359 atm = 272.8 torr

Pressure argon = 0.609 atm = 472.8 torr

Step 5: Calculate Total pressure

Ptotal = P(He)+P(Ar)

⇒ Pt  = total pressure of the gas mixture

⇒ P(He) = partial pressure of Helium

 ⇒ P(Ar)  = partial pressure of Argon

Pt = 272.8 torr + 472.8 torr

Pt = 745.6 torr

Total Pressure = 745.6 torr

Partial Pressure of He = 272.8 torr

Partial Pressure of Ar =  472.8 torr

5 0
4 years ago
What will happen if para starting movement do not occur or along the oesophagus​
Ilya [14]

Answer:

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8 0
3 years ago
In this equation, what should be the coefficients of the reactants and products? I2 + O2 → I4O9
Annette [7]
To balance the equation, you need to add coefficient so you have the same number of atoms on both sides of the reaction

balanced: 4 I₂ + 9 O₂ ---> 2 I₄O₉
6 0
3 years ago
The European Union's support for the Common Agricultural Policy illustrates why strategic trade policy is problematic. In this i
den301095 [7]

In this instance, the government was influenced by interest groups to the detriment of consumers

<u>Explanation:</u>

Interest groups perform a vital part in the manner that defines economic policy. Trade is a field where interest groups ought implied particularly noticeable. Groups depicting workers and firms appraised prominently in the assurance yielded the U.S. steel, automobile, textile, and footwear manufacturers.

Agricultural interests remained powerful and efficient in promoting the Common Agriculture Policy of the European Community. Interest groups and NGOs have frequently examined trade interventions.   Many policy sectors are now "congested" with an extended amount of interest groups, ending in struggles to transfer agreement in all policy sector

6 0
4 years ago
A 35.0-ml sample of 1.00 m kbr and a 60.0-ml sample of 0.600 m kbr are mixed. the solution is then heated to evaporate water unt
Ugo [173]
The number of moles in the resulting solution can be calculated by adding together the number of moles from the individual solution. That is calculated as follows,
   
     total number of moles = (35 mL)(1 L/1000 mL)(1 mole/L) + (60 mL)(1 L/1000 mL)(0.6 moles / L) = 0.071 moles

The precipitation reaction is,

      KBr + AgNO3 --> AgBr + KNO3

From the equation, each mole of the KBr will need one mole of AgNO3. Hence, 0.071 mole of AgNO3 will also be needed. Calculating for the mass,
  
          mass of AgNO3 = (0.071 moles)(169.87 g / mol) = 12.06 g

ANSWER: 12.06 grams


4 0
3 years ago
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