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Fantom [35]
3 years ago
12

The kinetic molecular theory describes the behavior of gases in terms of particles in?

Chemistry
1 answer:
Dominik [7]3 years ago
6 0
The answer is motion, this is what I would go with because when you are dealing with gases it puts motion in the term of particles.
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What are the stages of the life cycle of the sun
Jet001 [13]
The Sun is currently a main sequence star and will remain so for another 4-5 billion years. It will then expand and cool to become a red giant, after which it will shrink and heat up again to become a white dwarf. The white dwarf star will run out of nuclear fuel and slowly cool down over many billions of years.
5 0
2 years ago
Read 2 more answers
I need help with number 8 please help ASAP.
Rzqust [24]

Answer:

33.33% = 33%

Explanation:

MgCO3(s) + 2HCl (aq) --> MgCl2(aq) + H20(l) + CO2(g)

1 mole of MCO3 will produce → 1 mole of CO2

We need to get the number of mole of CO2:

and when we have 0.22 g of CO2, so number of mole = mass / molar mass

Moles = 0.22 g / 44 g/mol = 0.005 mole

Moles of Mg = moles of CO2 = 0.005 mole

Mass of Mg = moles * molar mass

= 0.005 * 84 /mol = 0.42 g

Percent of MgCO3 by mass of Mg = 0.42 g / 1.26 * 100

=33.33 %

8 0
3 years ago
Which of the following is a true
Katarina [22]

❤️Hello!❤️ The answer is A. Energy can change from one form to another. Hope this helps! ↪️ Autumn ↩️

5 0
3 years ago
Which number should be placed before H20 on the products side of the equation to
timama [110]
<h2>The required balanced equation:</h2><h2>C_3H_8 +5O_2 = 3CO_2 + 4H_2O</h2>

Explanation:

•  Propane when reacts with oxygen it gives carbon dioxide and water.

  • In order to make the equation balanced at both ends of the equation,  

Add 4 as a coefficient before on L.H.S (Left Hand Side) of Equation.

• Therefore, the required balanced equation is:

Propane, when added with 5 molecules of Water, yields 3 molecules of Carbon Dioxide and 4 molecules of water, as shown in the below equation -

C_3H_8 +5O_2 = 3CO_2 + 4H_2O

8 0
3 years ago
1. Calculate the number of moles of carbon dioxide formed when 40.0 moles of oxygen is consumed in the burning of propane. Note
Andrews [41]

Answer:

1. D (24.0 moles CO2)

2. A (.239 moles H2)

Explanation:

1. First Balance the equation

1 C3H8 + 5 O2 ---> 3 CO2 + 4 H2O

Then set up a stoiciometric equation so that the moles of O2 cancel out

40mol O2 x \frac{3 mole CO2}{5 mole O2} = 24.0 moles CO2

2. Set up a stoichiometric equation

10 grams Fe x \frac{1 mole Fe}{55.85 grams Fe} x \frac{4 mole H2}{3 mole Fe} = 0.239 moles H2

6 0
3 years ago
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