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nika2105 [10]
3 years ago
14

The points A(-3,6), B(8,6), C(8,-4)and D(-3,-4)are vertices of rectangle ABCD. A point is selected at random from the interior o

f this rectangle. What is the probability that the x-coordinate of the point is negative and the y-coordinate of the point is positive?
Mathematics
1 answer:
aleksklad [387]3 years ago
4 0

Answer:

the probability that the x-coordinate of the point is negative and the y-coordinate of the point is positive  is 16.36%

Step-by-step explanation:

Assuming that each point has the same probability to be chosen  ( uniform probability distribution in the rectangle area ) then the probability of choosing a negative x-coordinate and positive y-coordinate is the ratio of the area with those requirements over the total area of the rectangle.

therefore

Ar= area of negative x-values and positive y-values = (-3)*6 = 18

AT= total area of the rectangle = [8-(-3) ]*[6-(-4)] = 110

then

probability = Ar/AT = 18/110 = 0.1636 = 16.36%

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