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kirza4 [7]
4 years ago
7

A crew will arrive in one week and begin filming a city for a movie. The mayor is desperate to clean the city streets before fil

ming begins. Two teams are​ available, one that requires 200 hours and one that requires "400" hours. If the teams work​ together, how long will it take to clean all of the​ streets? Is this enough time before the cameras begin​ rolling?
Mathematics
1 answer:
Zigmanuir [339]4 years ago
6 0

Answer:

See below in bold.

Step-by-step explanation:

You work in fractions of the city streets done per hour:

1/200 + 1/400 = 1 /x  where x is the number of hours taken by 2 teams.

Multiply through by the LCM 400x:

2x + x = 400

3x = 400

x =  133.33 hours.

As there are 168 hours in a week they will have enough time.

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WHAT THE HECK IS THE ANSWER TO THIS -(3x+y)+2(x-4y)
Gnom [1K]

Answer:

-x -9y

Step-by-step explanation:

-(3x+y)+2(x-4y)

-3x -y +2x -2*4y

-x -y -8y

-x -9y

7 0
3 years ago
Read 2 more answers
Alabama Instruments Company has set up a production line to manufacture a new calculator. The rate of production of these calcul
kondaur [170]

Answer:

Calculators from the beginning of the third week to the end of the fourth week = 4048.

Step-by-step explanation:

We know that the rate of production of these calculators after t weeks is given by

\frac{dx}{dt} =5000(1-\frac{100}{(t+10)^{2}})

To find the number of calculators that have been produced in a period, we need to take the integral of the function above; the desired time is t=2 (beginning of third week) to t=4 (end of the fourth week). Therefore, the number of calculators produced in the given time is

\int\limits^4_2 {\frac{dx}{dt} } \, dt = \int\limits^4_2 {5000(1-\frac{100}{(t+10)^{2} }) } \, dt

Substitute t+10=u and dt=du, observe that the limits of integration will change

\int\limits^4_2 {\frac{dx}{dt} } \, dt => \int\limits^{14}_{12} {\frac{du}{dt} } \, dt

5000\int\limits^{14}_{12} { 1-\frac{100}{u^{2} } } \, du

5000(u+100u^{-1})\left \{ {{14} \atop {12}}\right.\\5000(2+\frac{100}{14}-\frac{100}{12} )\\4047.62 ≈ 4048

4 0
3 years ago
Mary has 50 earring boxes the boxes measure 1 inch on each side. How many rectangular prisms all with a different size base coul
Sholpan [36]
Given:
50 earring boxes with a measure of 1 inch each side

volume of boxes = a³ = 1³ = 1 in³
total volume of boxes = 1 in³ * 50 boxes = 50 in³

volume of a rectangular prism = length * width * height
50 in³ = length * width * height

Let us assume that the height is 1 in.

length and width can be factored:
50 x 1
25 x 2
10 x 5

<span>I can only make 3 rectangular prisms</span>
6 0
4 years ago
What is the answer???
bonufazy [111]
First, change one of the equations to an y=x form I'll use the top one for example.
3x-2y=14
-2y=14-3x
y=-7+(3/2)x
Not that you can show what y is in terms of x, plug in the x side of the equation into the other equation, for y.
x+2(-7+(3/2)x)=10
Now, you can solve for x
x-14+3x=10
4x-14=10
4x=24
x=6
Using this value of x, we can now solve for y using one of the original equations.
(6)+2y=10
2y=4
y=2
3 0
3 years ago
Helpppppppppppppppp pleaseeeee
Tcecarenko [31]

Answer:

<2=65 degrees

Step-by-step explanation:

Information provided:

Right angle=90

<25 degrees

Triangles add up to 180 degrees

90+25=115

180-115=65 degrees

Hope this helps! :)

6 0
3 years ago
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