You get the whole numbers (1's) out of it and show the left over fraction next to it. (e.g. there is 7/3 as a mixed number is 2 1/3 )
Option 3:
m∠ABC = 66°
Solution:
Given
and ABH is a transversal line.
m∠FAB = 48° and m∠ECB = 18°
m∠ECB = m∠HCB = 18°
<u>Property of parallel lines:
</u>
<em>If two parallel lines cut by a transversal, then the alternate interior angles are equal.</em>
m∠FAB = m∠BHC
48° = m∠BHC
m∠BHC = 48°
<u>Exterior angle of a triangle theorem:
</u>
<em>An exterior angle of a triangle is equal to the sum of the opposite interior angles.</em>
m∠ABC = m∠BHC + m∠HCB
m∠ABC = 48° + 18°
m∠ABC = 66°
Option 3 is the correct answer.
is proved
<h3><u>
Solution:</u></h3>
Given that,
------- (1)
First we will simplify the LHS and then compare it with RHS
------ (2)

Substitute this in eqn (2)

On simplification we get,


Cancelling the common terms (sinx + cosx)

We know secant is inverse of cosine

Thus L.H.S = R.H.S
Hence proved
Answer:
$15
Step-by-step explanation:
Simply divide 120 by 8 to get your answer.