Ask question

Ask question

All categories

My name is Ann [436]

3 years ago

15

Life gym charges a one-time fee to join of $40 and $20 each month. Write an equation that models the total cost, y, for x months

of being a member at this gym.

1 answer:

brilliants [131]3 years ago

8 0

Answer:

40+20x=y

Step-by-step explanation:

You might be interested in

A publishing company has just published a new college textbook. Before the company decides the price at which to sell this textb

Kobotan [32]

Answer:b

Step-by-step explanation:

8 0

3 years ago

8. A rectangle's sides are measured to be 6.2 cm and 9.3 cm. What is the

Zepler [3.9K]

A= 9.3 * 6.2
A = 57.66cm2

7 0

3 years ago

-5(-6k + 10) =<br> Help ASAP

Fudgin [204]

Answer:

<h2>30k - 50</h2><h2 />

Step-by-step explanation:

-5 (-6k + 10)

= 30k - 50

8 0

3 years ago

Quadrilateral ABCD is a rectangle. If AE = 36 and CE = 2x - 4, find x.<br> B<br> E<br> А.<br> D

krek1111 [17]

The value of the x is 20 if the quadrilateral ABCD is a rectangle and AE = 36 and CE = 2x - 4 because the diagonal of the rectangle bisect each other.

<h3>What is the area of the rectangle?</h3>

It is defined as the space occupied by the rectangle, which is planner 2-dimensional geometry.

The formula for finding the area of a rectangle is given by:

Area of rectangle = length × width

We know that the diagonal of the rectangle bisect each other.

AE = CE

36 = 2x - 4

2x = 40

x = 20

Thus, the value of the x is 20 if the quadrilateral ABCD is a rectangle and AE = 36 and CE = 2x - 4 because the diagonal of the rectangle bisect each other.

Learn more about the rectangle here:

brainly.com/question/15019502

#SPJ1

8 0

2 years ago

Use complete sentences to describe why √-1 ≠ -√1

tekilochka [14]

Well let's say that to compare these two numbers, we have to start with the definition first.

<u>D</u><u>e</u><u>f</u><u>i</u><u>n</u><u>i</u><u>t</u><u>i</u><u>o</u><u>n</u>

$\displaystyle \large{ {y}^{2} = x} \\ \displaystyle \large{ y = \pm \sqrt{x} }$

Looks like we can use any x-values right? Nope.

The value of x only applies to any positive real numbers for one reason.

As we know, any numbers time itself will result in positive. No matter the negative or positive.

<u>D</u><u>e</u><u>f</u><u>i</u><u>n</u><u>i</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>I</u><u>I</u>

$\displaystyle \large{ {a}^{2} = a \times a = |b| }$

Where b is the result from a×a. Let's see an example.

<u>E</u><u>x</u><u>a</u><u>m</u><u>p</u><u>l</u><u>e</u><u>s</u>

$\displaystyle \large{ {2}^{2} = 2 \times 2 = 4} \\ \displaystyle \large{ {( - 2)}^{2} = ( - 2) \times ( - 2) = | - 4| = 4}$

So basically, their counterpart or opposite still gives same value.

Then you may have a question, where does √-1 come from?

It comes from this equation:

$\displaystyle \large{ {y}^{2} = - 1}$

When we solve the quadratic equation in this like form, we square both sides to get rid of the square.

$\displaystyle \large{ \sqrt{ {y}^{2} } = \sqrt{ - 1} }$

Then where does plus-minus come from? It comes from one of Absolute Value propety.

<u>A</u><u>b</u><u>s</u><u>o</u><u>l</u><u>u</u><u>t</u><u>e</u><u> </u><u>V</u><u>a</u><u>l</u><u>u</u><u>e</u><u> </u><u>P</u><u>r</u><u>o</u><u>p</u><u>e</u><u>r</u><u>t</u><u>y</u><u> </u><u>I</u>

$\displaystyle \large{ \sqrt{ {x}^{2} } = |x| }$

Solving absolute value always gives the plus-minus. Therefore...

$\displaystyle \large{ y = \pm \sqrt{ - 1} }$

Then we have the square root of -1 in negative and positive. But something is not right.

As I said, any numbers time itself of numbers squared will only result in positive. So how does the equation of y^2 = -1 make sense? Simple, it doesn't.

Because why would any numbers squared result in negative? Therefore, √-1 does not exist in a real number system.

Then we have another number which is -√1. This one is simple.

It is one of the solution from the equation y^2 = 1.

$\displaystyle \large{ {y}^{2} = 1} \\ \displaystyle \large{ \sqrt{ {y}^{2} } = \sqrt{1} } \\ \displaystyle \large{ y = \pm \sqrt{1} }$

We ignore the +√1 but focus on -√1 instead. Of course, we know that numbers squared itself will result in positive. Since 1 is positive then we can say that these solutions exist in real number.

<u>C</u><u>o</u><u>n</u><u>c</u><u>l</u><u>u</u><u>s</u><u>i</u><u>o</u><u>n</u>

So what is the different? The different between two numbers is that √-1 does not exist in a real number system since any squared numbers only result in positive while -√1 is one of the solution from y^2 = 1 and exists in a real number system.

5 0

2 years ago

Read 2 more answers