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Paul [167]
4 years ago
13

Which is the graph of y = |3x| – 2?

Mathematics
1 answer:
s2008m [1.1K]4 years ago
4 0
Rat monkey eats hot dogs and dog poop
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(HELP) what is 10 1/2 ÷ 9 2/6 = ? (show ur work)
Readme [11.4K]

Answer:

9/8 or 1.125

Step-by-step explanation:

10 1/2 ÷ 9 2/6

= 21/2 ÷ 56/6

= 9/8

= 1.125

=》 See the attachment.

Hope it helps ⚜

8 0
2 years ago
Read 2 more answers
Which number is equivalent to 17/4
yaroslaw [1]
It's equivalent to 4.25 or 4 1/4
8 0
3 years ago
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Please help I will give brainliest!
Burka [1]
Answer: the statement “measure of <4 is 105 degrees” is incorrect.

Explanation: This is because since both angles 1 and 3 are vertical, this means they are both 95. This gives us 190 (95x2). Now we subtract this from 360 which gives us 170. Since angles 2 and 4 are vertical, we divide by 2, which gives us 85, not 105.

Hope this helps! :)
3 0
3 years ago
Suppose a particular type of cancer has a 0.9% incidence rate. Let D be the event that a person has this type of cancer, therefo
natita [175]

Answer:

There is a 12.13% probability that the person actually does have cancer.

Step-by-step explanation:

We have these following probabilities.

A 0.9% probability of a person having cancer

A 99.1% probability of a person not having cancer.

If a person has cancer, she has a 91% probability of being diagnosticated.

If a person does not have cancer, she has a 6% probability of being diagnosticated.

The question can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

In this problem we have the following question

What is the probability that the person has cancer, given that she was diagnosticated?

So

P(B) is the probability of the person having cancer, so P(B) = 0.009

P(A/B) is the probability that the person being diagnosticated, given that she has cancer. So P(A/B) = 0.91

P(A) is the probability of the person being diagnosticated. If she has cancer, there is a 91% probability that she was diagnosticard. There is also a 6% probability of a person without cancer being diagnosticated. So

P(A) = 0.009*0.91 + 0.06*0.991 = 0.06765

What is the probability that the person actually does have cancer?

P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.91*0.009}{0.0675} = 0.1213

There is a 12.13% probability that the person actually does have cancer.

3 0
3 years ago
Find the length of the third side. If necessary, round to the nearest tenth.<br> 15<br> 9
mihalych1998 [28]

Answer:

10

Step-by-step explanation:

7 0
3 years ago
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