Question

What is the solution to the equation (Y/y-4) - (4/y+4) = (32/y^2-16)

Answer 1

Answer:

No solution

Step-by-step explanation:

$\frac{y}{y-4} -\frac{4}{y+4}=\frac{32}{y^2-16}$

LEts factor y^2-16 to find out LCD

$y^2-16= y^2-4^2= (y+4)(y-4)$

$\frac{y}{y-4} -\frac{4}{y+4}=\frac{32}{ (y+4)(y-4)}$

LCD is (y+4)(y-4)

Multiply each fraction with LCD

$y(y+4)-4(y-4)= 32$

$y^2+4y-4y+16= 32$

Subtract 32 from both sides and combine like terms

$y^2-16= 0$

$(y+4)(y-4)= 0$

SEt each factor =0 and solve for y

$y+4=0 , y= -4$

$y-4=0 , y=4$

So the value of y are -4 and 4

When y=4 and -4 the denominator of original function becomes 0 that is undefined. so y values are not solutions for the given equation

No Solution for this equation

Answer 2

y2 = −(−4) + √ (−4)2 − 4×9×(−32)  2×9 = 4 + 4 × √ 73  18 ≈ 2.121          If im wrong you have the right to slap me in the face