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3 years ago

Fill in the table using this function rule y=-6x+3x-5-101

Mathematics

2 answers:

pochemuha3 years ago

6 0

(-5, 33)
(-1,9)
(0,3)
(1,-3)

ch4aika [34]3 years ago

6 0

Answer:

hope this helps

good luck! have a good day!!

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How do you solve this step by step??

KonstantinChe [14]

Answer:

Step-by-step explanation: 6x+5x=3x+2x-54

11x=5x-54

+5x +5x

16x=54

16 16

x=3.375

3 0

3 years ago

What is the length of one leg of the triangle? 64 cm 64 StartRoot 2 EndRoot cm 128 cm 128 StartRoot 2 EndRoot cm.

zmey [24]

Answer:

Use the Pythagorean theorem for right triangles to solve this

a^2 + b^2 = c^2 where 'a' and 'b' are the legs of the triangle and 'c' is the hypotenuse

so:

8^2 + b^2 = 17^2 solve for the second leg, b

64 + b^2 = 289

b^2 = 289 - 64= 225

b = 15

7 0

3 years ago

sophia had pieces of rope that were 3 1/5 feet long 4.5 feet long and 5 3/10 feet long 4.5 feet long and 5 3/10 feet long what w

Dennis_Churaev [7]

5/9 of a foot

Step-by-step explanation:

Divide 5 by 9 to find the length for 9 equal pieces

6 0

3 years ago

Read 2 more answers

A certain shade of green paint is made from 5 parts yellow mixed with three parts blue. If 2 cans of yellow are used, how many c

vekshin1

5 Yellow = 3 Blue
2 Yellow = 3/5 *2 = 6/5 Blue, 1.2 cans of Blue .
<u>Award brainliest if helped!</u>

6 0

4 years ago

Help! If you know this can you tell me how to do it?

aleksandr82 [10.1K]

Answer:

Step-by-step explanation:

Here's how this works:

Get everything together into one fraction by finding the LCD and doing the math. The LCD is sin(x) cos(x). Multiplying that in to each term looks like this:

$[sin(x)cos(x)]\frac{sin(x)}{cos(x)}+[sin(x)cos(x)]\frac{cos(x)}{sin(x)} =?$

In the first term, the cos(x)'s cancel out, and in the second term the sin(x)'s cancel out, leaving:

$\frac{sin^2(x)}{sin(x)cos(x)}+\frac{cos^2(x)}{sin(x)cos(x)}=?$

Put everything over the common denominator now:

$\frac{sin^2(x)+cos^2(x)}{sin(x)cos(x)}=?$

Since $sin^2(x)+cos^2(x)=1$ , we will make that substitution:

$\frac{1}{sin(x)cos(x)}$

We could separate that fraction into 2:

$\frac{1}{sin(x)}$ × $\frac{1}{cos(x)}$

$\frac{1}{sin(x)}=csc(x)$ and $\frac{1}{cos(x)}=sec(x)$

Therefore, the simplification is

sec(x)csc(x)

5 0

3 years ago