Answer and Explanation:
Given data:
Distance (D) = 40 KM
Speed of light in the fiber =Distance/ speed of light in the fiber
a) Delay (P) = Distance/ speed of light in the fiber
= (40,000 Meters/2×108 m/s)
=( 40×103 Meters/2×108 m/s)
Propagation delay (P) = 0.0002 seconds or 200 microseconds
b)
if propagation delay is 0.0002 Seconds roundup trip time (RTT) will be 0.0004 Seconds or 400 micro Seconds
Essentially since transmission times and returning ACKs are insignificant all we really need is a value slightly greater than 0.0004 seconds for our timeout value.
c)
The obvious reasons would be if the data frame was lost, or if the ACK was lost. Other possibilities include extremely slow processing on the receive side (late ACK).
Or Extremely Slow Processing of the ACK after it is received back at the send side.
Answer:
something specific a person wants to achieve m8
Explanation:
Answer:
The characteristic that is violated is Availability.
Explanation:
- The network is passing data at mostly, it means performance is good. Junior network engineer is doing his job well then there is minimum chance of network failure or lack of manageability.
- The scalability; range of computing capabilties can be managed by the engineer.
- However, sometimes the core router might get crashed due to unavailability of the network that is not under the control of the engineer.
