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3 years ago

Which element has 5 outer electrons in its 3rd shell?

Chemistry

2 answers:

Sloan [31]3 years ago

5 0

Answer:

Explanation:

Each shell can contain only a fixed number of electrons: The first shell can hold up to two electrons, the second shell can hold up to eight (2 + 6) electrons, the third shell can hold up to 18 (2 + 6 + 10) and so on.

...

List of elements with electrons per shell.

Z 5

Element Boron

No. of electrons/shell 2, 3

Group 13

Debora [2.8K]3 years ago

5 0

Answer:

Phosphorus

Explanation:

Phosphorus has 15 total electrons. Its first shell can hold 2 electrons. Its second shell can hold 8 electrons. The remaining 5 electrons are in its third shell (the third shell can hold up to 18 electrons).

2 electrons (1st shell) + 8 electrons (2nd shell) + 5 electrons (3rd shell) = 15 total electrons (the number of electrons P has).

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The downward force created by mass that is directly related to the force of gravity acting upon it is?

Allisa [31]

Answer:

The answer is weight

7 0

3 years ago

Read 2 more answers

2. The temperature of a gas is increased from 125⁰C to 182⁰C inside of a rigid container. The original pressure of the gas was 1

Lina20 [59]

P1/T1 = P2/T2

125⁰C = 398.15 k

182⁰C = 455.15 k

1.22/398.15 = p2/455.15

p2= 1.39atm

the pressure of the gas be after the temperature change is 1.39 atm

7 0

3 years ago

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Which of the following equations represents an unbalanced neutralization reaction equation? a) HBr + Ca(OH)2 → CaBr2 + H2O b) SO

katrin2010 [14]

When you have to balance an equation it means that you have to balance both parts of equation so that the numbers of each elements will have the same amount. According to this rule, it is quite easy to distinguish unbalanced reaction, and the answer is a) HBr + Ca(OH)2 → CaBr2 + H2O as you can see that amount of oxygen on both sides is not the same.

4 0

4 years ago

Read 2 more answers

Please help me like now please

777dan777 [17]

Answer:

1-1) NaHCO3 + CH3COOH --> NaCH3COO + H2O + CO2

1-2) 0.5 mole of CO2

2-1) 2C4H10 + 13O2 --> 8CO2 + 10H2O

2-2) 4 mol CO2

Explanation:

Question 1

NaHCO3 + CH3COOH --> NaCH3COO + H2O + CO2

To balance the equation, count the number of atoms on both sides of the equation

(1 Na, 1+3+1H, 1+1+1C, 3+2Oxygen) --> (1 Na, 1+1+1C, 3+2H, 2+1+2Oxygen)

Combining the pluses will give you the following

(1 Na, 5H, 3C, 5Oxygen) --> (1 Na, 3C, 5H, 5Oxygen)

Both sides are the same, therefore the chemical equation is balanced (originally).

From the equation, we can see that 1 mole of NaHCO3 produces 1 mole of CO2.

So that means 0.5 mole of NaHCO3 would produce 0.5 mole of CO2.

Question 2

C4H10 + O2 --> CO2 + H2O

Again, count the number of atoms on both sides of the equation

(4C, 10H, 2O) --> (1C, 2H, 3O) This time left does not equal right side

You now need to find factors that can make both sides equal.

C4H10 + O2 --> 4CO2 + H2O Now the C is balanced, let's recount 

(4C, 10H, 2Oxygen) --> (4C, 8+1Oxygen, 2H) H&O is still not balanced

C4H10 + O2 --> 4CO2 + 5H2O Now the H is balanced, let's recount

(4C, 10H, 2Oxygen) --> (4C, 8+5Oxygen, 10H) O is still not balanced

C4H10 + (13/2)O2 --> 4CO2 + 5H2O Now the O is balanced

(4C, 10H, 13Oxygen) --> (4C, 13Oxygen, 10H)

But because 13/2 is a fraction, we want to eliminate that by multiplying every reactant and product by 2 (the denominator).

2C4H10 + 13O2 --> 8CO2 + 10H2O Now it's completely balanced!

(8C, 20H, 28Oxygen) --> (8C, 28Oxygen, 20H) Yayy! It's balanced.

Now, 2 mol C4H10 produces 8 mol CO2.

So 1 mol C4H10 produces 4 mol CO2.

6 0

3 years ago

What is the mass of an object that has a total heat loss of 550. cal, a specific heat of

Galina-37 [17]

Answer:

the mass is .587 J/g°C

Explanation:

................

4 0

3 years ago