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baherus [9]
2 years ago
8

How many grams of chromium (Cr) are present in 4.20 moles of the metal?

Chemistry
1 answer:
stira [4]2 years ago
8 0
420 eyyyyyyyy        Only joking,    the Mr of Cr ≈ 52       mass = molar mass*moles        mass of Cr = 4.2* 52 = 218.4g          If given 4.20, 3 significant figures is appropriate, so it would be 218g
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Which of the following would be expected to have the highest viscosity? CH3CH2OH, HOCH2OH, CH3CH2CH3
zaharov [31]

Answer: Out of the given options HOCH_{2}OH is expected to have the highest viscosity.

Explanation:

The resistance occurred in the flow of a liquid substance is called viscosity.

More stronger is the intermolecular forces present in a substance more will be its resistance in its flow. Hence, more will be its viscosity.

For example,  HOCH_{2}OH has strong intermolecular hydrogen bonding than the one's present in CH_{3}CH_{2}OH and CH_{3}CH_{2}CH_{3}. This is because two-OH groups are present over here.

Thus, we can conclude that out of the given options HOCH_{2}OH is expected to have the highest viscosity.

5 0
2 years ago
Please answer truthfully:))​
makvit [3.9K]

Answer:

Fast, Direction, Time

Explanation:

4 0
2 years ago
What is the most likely reason a computer model is used for a black hole?
Rashid [163]

Answer:

Black holes are merely the most exotic example of the general principle that ... quantum computer stores bits on protons and uses magnetic fields to flip them. ... Powered by Standard Model software, the universe computes

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6 0
2 years ago
What mass of NaC6H5COO should be added to 1.5 L of 0.40 M C6H5COOH solution at 25 °C to produce a solution with a pH of 3.87 giv
statuscvo [17]

Answer:

41 g

Explanation:

We have a buffer formed by a weak acid (C₆H₅COOH) and its conjugate base (C₆H₅COO⁻ coming from NaC₆H₅COO). We can find the concentration of C₆H₅COO⁻ (and therefore of NaC₆H₅COO) using the Henderson-Hasselbach equation.

pH = pKa + log [C₆H₅COO⁻]/[C₆H₅COOH]

pH - pKa = log [C₆H₅COO⁻] - log [C₆H₅COOH]

log [C₆H₅COO⁻] = pH - pKa + log [C₆H₅COOH]

log [C₆H₅COO⁻] = 3.87 - (-log 6.5 × 10⁻⁵) + log 0.40

[C₆H₅COO⁻] = [NaC₆H₅COO] = 0.19 M

We can find the mass of NaC₆H₅COO using the following expression.

M = mass NaC₆H₅COO / molar mass NaC₆H₅COO × liters of solution

mass NaC₆H₅COO = M × molar mass NaC₆H₅COO × liters of solution

mass NaC₆H₅COO = 0.19 mol/L × 144.1032 g/mol × 1.5 L

mass NaC₆H₅COO = 41 g

7 0
2 years ago
What is the square root of 25
Sauron [17]

Answer:

5

Explanation:

because 5x5 = 25

and 25 ÷5= 5

4 0
3 years ago
Read 2 more answers
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