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baherus [9]
2 years ago
8

How many grams of chromium (Cr) are present in 4.20 moles of the metal?

Chemistry
1 answer:
stira [4]2 years ago
8 0
420 eyyyyyyyy        Only joking,    the Mr of Cr ≈ 52       mass = molar mass*moles        mass of Cr = 4.2* 52 = 218.4g          If given 4.20, 3 significant figures is appropriate, so it would be 218g
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Answer: 2.4 ml

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Given,: 28% w/w of NH_3 solution means 28 g of ammonia in 100 g of solution.

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Now we have to calculate the volume of solution.

Volume=\frac{Mass}{Density}=\frac{100g}{0.899g/ml}=111.2ml  

Molarity : It is defined as the number of moles of solute present in one liter of solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n = moles of solute NH_3=\frac{\text {given mass}}{\text {molar mass}}=\frac{28}{17}=1.65moles

V_s = volume of solution in liter = 0.11 L

Now put all the given values in the formula of molarity, we get

Molarity=\frac{1.65moles}{0.11L}=15mole/L

Using molarity equation:

M_1V_1=M_2V_2

15\times V_1=0.036\times 1.0\times 10^{3}

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3 years ago
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5 0
2 years ago
Read 2 more answers
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