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MrRa [10]
3 years ago
14

Pleaseeeeeeeeeee helpppppppppppppppp

Chemistry
2 answers:
andreyandreev [35.5K]3 years ago
6 0

Answer:

True

Explanation:

djyliett [7]3 years ago
5 0

Answer:

True

Explanation:

It releases carbon dioxide in the Pulmonary Artery

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Give two possible reasons why using tap water instead of distilled water could give misleading
hodyreva [135]

Answer:

Explanation:

Public tap water is not desirable when carrying out experiments in the laboratory.

The chemical definition of water is a compound made up of two atoms of hydrogen to 1 atom of oxygen. Any violation simply desist from the true meaning of water.

Why are tap water not used:

  • They contain other dissolved ions like chlorine which have been added in their treatment. This alters the fundamental molecules that is expected to be seen in water. Water of this nature can affect experimental results seriously.
  • Tap water can become a mixture instead of a simple compound. A mixture is a combination of several compounds. Such water will have a varied composition and make simplification of experiments very difficult.
7 0
3 years ago
If a rock had a mass of 20g explain how you would fund the density
REY [17]

Answer:

you have to divide it

Explanation:

4 0
2 years ago
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Easy Questions! Chemistry - Please help! I give thanks
Evgen [1.6K]
This is not chemistry but

see it is a triangular prim on it's side
V=BH
are of base times height
the base is a triangle
height is 18.5

base=1/2bh
b=8.6
h=8.4
base=1/2(8.6)(8.4)
base=36.12

V=bh
V=36.12*18.5
V=668.22

round
V=668.2 ft^3
8 0
3 years ago
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Calculate the hydronium ion and hydroxide ion concentrations in human blood at 25oc
sukhopar [10]

Using the equation, pH = − log [H+] , we can solve for [H+] as,

− pH = log [H+] ,

[H+] = 10−pH.

Exponentiate both sides with base 10 to "undo" the common logarithm. The hydrogen ion concentration of blood with pH 7.4 is,

[H+] = 10−7.4 ≈ 0.0000040 = 4.0 × 10−8 M.

5 0
3 years ago
Separate this redox reaction into its balanced component half-reactions. What is the oxidation and reduction half reactions
erma4kov [3.2K]
<span>Separate this redox reaction into its component half-reactions. 
Cl2 + 2Na ----> 2NaCl 

reduction: Cl2 + 2 e- ----> 2Cl-1 
oxidation: 2Na ----> 2Na+ & 2 e- 


2) Write a balanced overall reaction from these unbalanced half-reactions: 

oxidation: Sn ----> Sn^2+ & 2 e- 
reduction: 2Ag^+ & 2e- ----> 2Ag 

giving us 
2Ag^+ & Sn ----> Sn^2+ & 2Ag </span>Steve O <span>· 5 years ago </span><span>
</span>
3 0
3 years ago
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