Answer:
See explanation below
Explanation:
This reaction is known as the Grignard reaction. If's often used to add an alkyl to a molecule, in this case, a ketone. This also helps to reduce the carbonile to an alcohol.
The mechanism is taking place in 3 steps.
The first step involves the attack of the pair of electrons of the oxygen from the cyclohexanone to the MgBr, and the other pair takes the propyl.
The second step involves the breaking of this bond to have the OMgBr and the propyl attached to the carbon of the chain.
The last steps involves an hydration of the molecule, to turn the OMgBr into OH, and that would be the final product.
In this case, the final product will be 1-propyl-cyclohexanol.
The picture below, shows the mechanism and the drawing of the final product.
Answer:
Explanation:
Hello,
In this case, the reaction is:
Thus, the law of mass action turns out:
![Kc=\frac{[CH_3CH_2OH]_{eq}}{[H_2O]_{eq}[CH_2CH_2]_{eq}}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BCH_3CH_2OH%5D_%7Beq%7D%7D%7B%5BH_2O%5D_%7Beq%7D%5BCH_2CH_2%5D_%7Beq%7D%7D)
Thus, since at the beginning there are 29 moles of ethylene and once the equilibrium is reached, there are 16 moles of ethylene, the change 
result:
![[CH_2CH_2]_{eq}=29mol-x=16mol\\x=29-16=13mol](https://tex.z-dn.net/?f=%5BCH_2CH_2%5D_%7Beq%7D%3D29mol-x%3D16mol%5C%5Cx%3D29-16%3D13mol)
In such a way, the equilibrium constant is then:
Thereby, the initial moles for the second equilibrium are modified as shown on the denominator in the modified law of mass action by considering the added 15 moles of ethylene:
Thus, the second change, 
finally result (solving by solver or quadratic equation):
Finally, such second change equals the moles of ethanol after equilibrium based on the stoichiometry:
Best regards.
That Atoms are indivisible components of matter, but it has been modified since atoms contains molecules.
Re enema ughh ten Hessian
First convert grams to moles:
90.0g *(mole/39.997) = 2.250mole
Remember that molarity is moles per liters:
2.250mol/3L = .750 M
