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viktelen [127]
3 years ago
7

*A 0.145 kg baseball reaches a speed of 36 m/s from rest when a bat strikes. If the average force of 500 N was applied on the ba

ll by the bat, what is the impact time?
Physics
1 answer:
Oksana_A [137]3 years ago
6 0

Answer:

Impact time is 0.01 seconds.

Explanation:

Express the eventual speed in terms of the average acceleration, impact time and initial velocity (which is 0 in our case):

v = a\cdot t + v_0 = a\cdot t

The average acceleration is the result of applying an average force as given. The duration of the impact can be determined as follows:

v = a\cdot t = \frac{F}{m}t\implies t=\frac{vm}{F}= \frac{36\frac{m}{s}\cdot 0.145 kg}{500kg\frac{m}{s^2}}=0.010 s

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Explanation:

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This means that if sin(w*t) describes this situation, we have that:

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3 years ago
which has a higher acceleration:a 10kg object acted upon with a net force of 20N or an 18kg object acted on by a net force of 20
MA_775_DIABLO [31]
<span>Answer: The acceleration of 10 kg object is greater than that of 18 kg object.

Explanation:
According to Newton's Second law:
F = ma --- (A)

Let's find the acceleration for both 10 kg and 18 kg objects!
The net force on both of these masses = F = 20N

(1) Acceleration of 10 kg object
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20 = 10 * a
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(2) Acceleration of 18 kg object
Mass = m = 18 kg
Plug in the values in equation (A):

20 = 18 * a
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2 > 1.11; therefore, 10 kg object has the higher acceleration compared to the acceleration of the 18 kg object.</span>
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