Question

*A 0.145 kg baseball reaches a speed of 36 m/s from rest when a bat strikes. If the average force of 500 N was applied on the ball by the bat, what is the impact time?

Answer 1

Answer:

Impact time is 0.01 seconds.

Explanation:

Express the eventual speed in terms of the average acceleration, impact time and initial velocity (which is 0 in our case):

$v = a\cdot t + v_0 = a\cdot t$

The average acceleration is the result of applying an average force as given. The duration of the impact can be determined as follows:

$v = a\cdot t = \frac{F}{m}t\implies t=\frac{vm}{F}= \frac{36\frac{m}{s}\cdot 0.145 kg}{500kg\frac{m}{s^2}}=0.010 s$