a mass m at the end of a spring oscillates with a frequency of 0.78 hz . when an additional 730 g mass is added to m, the freque
1 answer:
The value of mass m = 0.506kg
Initial frequency = 0.78Hz
additional mass = 730 g = 0.73kg
New frequency = 0.65 Hz
F = 1/2π
0.78 = 1/2π
additional mass,
0.65 = 1/2π
1.44 = k/m / k/m+0.73
1.44 = m+0.73 / m
1.44m -m = 0.73
1.44m = 0.73
mass m = 0.506kg
a measurement used in physics to express the inertia, a quality that all matter has in common. Effectively, it is the resistance a body of matter offers to a change in its speed or position as a result of the application of a force. The change caused by an applied force is proportional to the mass of the body. The kilograms is the measure of mass in the International System of Units (SI). Its definition is based on the Planck constant, which is set at 6.62607015 1034 joule second. The unit of energy known as a joule is one kilogramme times one square metre per second. The kilogramme is determined by precise measurements of Planck's constant, while the second and metre are already defined in terms of other physical constants.
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To solve this problem we will apply the concepts related to the wavelength of its third harmonic.
It describes that the wavelength is equivalent to
Here,
The wavelength is in turn described as a function that depends on the change of the speed as a function of the frequency, that is to say
In this case the speed is equivalent to the speed of sound and the frequency was previously given, therefore
Finally the length of the pipe would be
2s
Explanation:
Given parameters:
Current = 0.835A
Quantity of charge = 1.67C
Unknown:
Time taken = ?
Solution:
The quantity of electricity Q in coulombs is the product of the current I and time t.
Q = I x t
Q is the quantity of electricity in coulombs
I is the current
t is the time taken
input the values and solve for t;
1.67 = 0.835 x t
t = = 2s
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