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Marrrta [24]
3 years ago
9

A train having speed of 85 km/h takes 5 hours to travel from Kerala to Karnataka. Calculate the distance between Kerala and Karn

ataka
Physics
1 answer:
Morgarella [4.7K]3 years ago
6 0

Answer:

the distance between Kerala and Karnataka is 425 km.

Explanation:

Given;

speed of the train, u = 85 km/h

time taken for the train to travel from Kerala to Karnataka, t = 5 hours

The distance between Kerala and Karnataka is calculated as;

Distance = speed x time

Distance = 85 km/h  x  5 h

Distance = 425 km

Therefore, the distance between Kerala and Karnataka is 425 km.

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bixtya [17]

Answer:

The unit of speed is m/s.

7 0
3 years ago
you give a shopping cart a job down the aisle the cart is full of groceries and has a mass of 18 kilograms the cart accelerates
mezya [45]

                 Force = (mass) x (acceleration)

                 Force = (18 kg) x (3 m/s²) = 54 newtons

As long as you continue pushing the cart with 54 newtons of force,
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At the instant you release it, or keep your hands on it but stop pushing,
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3 years ago
Read 2 more answers
Blood in a carotid artery carrying blood to the head is moving at 0.15 m/s when it reaches a section where plaque has narrowed t
sp2606 [1]

Answer:

26.9 Pa

Explanation:

We can answer this question by using the continuity equation, which states that the volume flow rate of a fluid in a pipe must be constant; mathematically:

A_1 v_1 = A_2 v_2 (1)

where

A_1 is the cross-sectional area of the 1st section of the pipe

A_2 is the cross-sectional area of the 2nd section of the pipe

v_1 is the velocity of the 1st section of the pipe

v_2 is the velocity of the 2nd section of the pipe

In this problem we have:

v_1=0.15 m/s is the velocity of blood in the 1st section

The diameter of the 2nd section is 74% of that of the 1st section, so

d_2=0.74d_1

The cross-sectional area is proportional to the square of the diameter, so:

A_2=(0.74)^2 A_1=0.548 A_1

And solving eq.(1) for v2, we find the final velocity:

v_2=\frac{A_1 v_1}{A_2}=\frac{A_1 (0.15)}{0.548 A_1}=0.274 m/s

Now we can use Bernoulli's equation to find the pressure drop:

p_1 + \frac{1}{2}\rho v_1^2 = p_2 + \frac{1}{2}\rho v_2^2

where

\rho=1025 kg/m^3 is the blood density

p_1,p_2 are the initial and final pressure

So the pressure drop is:

p_1 - p_2 = \frac{1}{2}\rho (v_2^2-v_1^2)=\frac{1}{2}(1025)(0.274^2-0.15^2)=26.9 Pa

8 0
3 years ago
Nuclear
luda_lava [24]

Answer:

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3 years ago
A car starts from rest and accelerates to 14 m/s in 2 seconds. What was its acceleration
Romashka [77]

Answer:

7m/s^2

Explanation:

using v=u+at

since the car started from rest, u=0 , v=14m/s t=2s

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7 0
2 years ago
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