This is a ratio problem; the ratio of the length to width is constant (and therefore equal):
4 /6 = 15 / x
Now, with a ratio, we may do any allowable algebra operation: cross-multiply, invert both sides, multiply or divide both sides by the same amount, etc.
Let's cross-multiply:
4x = (15)(6)
x = 90/4
x = 22.5 in.
Answer:
4. A
5. B
Step-by-step explanation:
4. I'll solve question four first:
The two marked points on the line are (-2, -3)&(2, 5). Using the formula to find slope(y2-y1/x2-x1), substitute in the points.
5--3/2--2 or 8/4;simplified to 2/1 or 2.
Now use point-slope form: y-y1 = m(x-x1)
y--3 = 2(x--2): Substitute in the values of y1, m, and x1.
y+3 = 2x + 4: Distribute.
y = 2x + 1: Subtract three from both sides.
5. Do the same for question 5.
The first point is (-4, 2), the second point is (4, -1).
-1-2/4--4; -3/8.
Now use point-slope form:
y-2 = -3/8x -12/8: Substitute in the values of x1, y1, m, and distribute the slope to the parentheses.
y = -3/8x + 1/2
Answer:
1/4 of them were rotten
rotten ones = 1/4 × 12 = 3
ones that weren't rotten = 12 - 3 = 9
Line BE and KE are the same length, so set the 2 equations to equal and solve for P.
7p+7 = 37-3p
Add 3 p to both sides:
10p +7 = 37
Subtract 7 from each side:
10p = 30
Divide both sides by 10:
p = 30/10
p = 3
The answer is B.
Solution given:
y=70x+
Comparing above equation with y=mx+c
we get
m=70
So
<u>Slope</u><u>=</u><u>7</u><u>0</u>
