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vova2212 [387]
3 years ago
8

Kuri spent a total of $68 on trading cards. His collection contains two types of cards. A pack of trading card A $4 and a pack o

f trading card b cost $7. HOW many packs of each trading card were purchased if the total number of packs is 11?​
Mathematics
2 answers:
masya89 [10]3 years ago
8 0

Answer:

8 of Card B and 3 of card A. Hope this helps

inysia [295]3 years ago
8 0

Answer:

Kuri purchased 3 packs of trading card A, and 8 packs of trading card B.

Step-by-step explanation:

1. First name the variables:

a = number of packs of trading card A

b = number of pack of trading card B

2. As a pack of trading card A costs $4, a pack of trading card b costs $7 and As Kuri spent a total of %68 on trading cards, the first equation is:

4a+7b=68 (Eq.1)

3. As Kuri purchased a total number of 11 packs, the second equation is:

a+b=11 (Eq.2)

4. Solve Eq.2 for a:

a+b=11\\\\a=11-b (Eq.3)

5. Replace Eq.3 in Eq.1 and solve por b:

4(11-b)+7b=68\\\\44-4b+7b=68\\\\-4b+7b=68-44\\\\3b=24\\\\b=\frac{24}{3}\\\\b=8

6. Replace the value of b in Eq.3:

a=11-8\\\\a=3

Therefore Kuri purchased 3 packs of trading card A, and 8 packs of trading card B.

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The painting shown at the right has an area of 220. What is the value of x?
tangare [24]

Answer:

9.76

Step-by-step explanation:

area of a rectangle = length * breadth

length = (2x + 3)

breadth = x

given area is 220 sq. inches.

thus,

220 = x * (2x+3)

220 = 2x² +3x

2x² + 3x -220 = 0

x = (-b + √ ( b²-4ac) ) ÷ 2a

x = ( -3 + √ ( 3² - 4*2*220) ) ÷ 2*2

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5 0
3 years ago
Jennifer's basketball team played 18 games this season, and they won twice as many games as they lost. How many games did they l
irakobra [83]
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6 0
3 years ago
Peter's farm has 160 meters of fencing, and he wants to fence a rectangular field thatborders a straight river. He needs no fenc
Likurg_2 [28]

ANSWER

3200 m²

EXPLANATION

Peter wants to build a fence around a rectangular field, except for one side because the river is there,

So, the total perimeter of the fence is,

P=W+W+L=2W+L

And this is equal to 160 m. Solving for L,

160=2W+L\text{ }\Rightarrow\text{ }L=160-2W

The area of this field is,

A=WL

Replace L with the expression we found from the perimeter,

A=W(160-2W)=160W-2W^2

The area is given by a quadratic function whose leading coefficient is negative, which means that the graph is a downward parabola and, therefore, the vertex is the maximum value of the area.

The x-coordinate of the vertex is given by,

f(x)=ax^2+bx+c\text{ }\Rightarrow\text{ }x_{vertex}=\frac{-b}{2a}

In this case, x is W, a = -2, and b = 160, so the width of the field for the maximum area is,

W_{vertex}=\frac{-160}{2(-2)}=\frac{160}{4}=40m

And the length when W = 40 is,

L=160-2W=160-2\cdot40=160-80=80m

And the area is,

A=WL=40m\cdot80m=3200m^2

Hence, the largest area of Peter's farm that can be fenced is 3200 square meters.

5 0
1 year ago
Please help me create a truth table for the statement p^(qv~p)
enyata [817]
Hello,

1)  p∧(q∨¬p)=(p∧q)∨(p∧¬p)=p∧q proof:

2)

p|q|¬p|q∨¬p|p∧(q∨¬p)|p∧q
0|0|..1|.......1|..............0|0
0|1|..1|.......1|..............0|0
1|0|..0|.......0|..............0|0
1|1|..0|.......1|..............1|1



7 0
3 years ago
Help Asap please).The total cost after tax to repair Deborah's computer is represented by 0.08 (50h) +50h, where h represents th
Svet_ta [14]

Answer:

0.08(50h)

Step-by-step explanation:

0.08 (50h) +50h \\  =  \frac{8}{100} (50h) + 50h \\  = 8\%(50h) + 50h \\

Since, it took 50h to repair the computer so, 0.08(50h) represents the amount of tax Deborah has to pay. Which is 8% of 50h.

7 0
3 years ago
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