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vova2212 [387]
3 years ago
8

Kuri spent a total of $68 on trading cards. His collection contains two types of cards. A pack of trading card A $4 and a pack o

f trading card b cost $7. HOW many packs of each trading card were purchased if the total number of packs is 11?​
Mathematics
2 answers:
masya89 [10]3 years ago
8 0

Answer:

8 of Card B and 3 of card A. Hope this helps

inysia [295]3 years ago
8 0

Answer:

Kuri purchased 3 packs of trading card A, and 8 packs of trading card B.

Step-by-step explanation:

1. First name the variables:

a = number of packs of trading card A

b = number of pack of trading card B

2. As a pack of trading card A costs $4, a pack of trading card b costs $7 and As Kuri spent a total of %68 on trading cards, the first equation is:

4a+7b=68 (Eq.1)

3. As Kuri purchased a total number of 11 packs, the second equation is:

a+b=11 (Eq.2)

4. Solve Eq.2 for a:

a+b=11\\\\a=11-b (Eq.3)

5. Replace Eq.3 in Eq.1 and solve por b:

4(11-b)+7b=68\\\\44-4b+7b=68\\\\-4b+7b=68-44\\\\3b=24\\\\b=\frac{24}{3}\\\\b=8

6. Replace the value of b in Eq.3:

a=11-8\\\\a=3

Therefore Kuri purchased 3 packs of trading card A, and 8 packs of trading card B.

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9 would be the differance 124-115+1-1=9
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A large company put out an advertisement in a magazine for a job
vova2212 [387]

Answer:

<em>C(19)=12 responses</em>

Step-by-step explanation:

<u>Exponential Decay Function</u>

The exponential function is frequently used to model natural growing or decaying processes, where the change is proportional to the actual quantity.

An exponential decaying function can be expressed as follows:

C(t)=C_o\cdot(1-r)^t

Where:

C(t) is the actual value of the function at time t

Co is the initial value of C at t=0

r is the decaying rate, expressed in decimal

The company puts out an advertisement for a job opening. Initially, the company got 90 responses to the advertisement. Each day, the responses declined by 10%.

This is an example where the decay model can be used to calculate the responses to the advertisement at the day t.

The initial value is Co=90, the decaying rate is r=10% = 0.10. The model is written as:

C(t)=90\cdot(1-0.1)^t

Calculating:

C(t)=90\cdot(0.9)^t

We are required to calculate the number of responses at day t=19, thus:

C(19)=90\cdot(0.9)^{19}

C(19)=12 responses

8 0
3 years ago
The perimeter of the shape is
jasenka [17]

Answer:

94 cm.

Step-by-step explanation:

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= 94 cm.

8 0
3 years ago
Help please i’ll give extra points
yKpoI14uk [10]

Answer:

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7 0
2 years ago
Read 2 more answers
PLEASE HELP!!!!!
Zielflug [23.3K]
Question #1

Part A:
The y-intercept can be found when x = 0. If you look at your table, when x = 0, y = 5. So the y-intercept is 5.

Part B:
\sf Slope = \frac{27-5}{1-0} = \frac{22}{1} = \boxed{22}
The slope is 22.

Part C:
y = mx + b
y = 22x + 5

We are given 225 as the range, or in place of y.
225 = 22x + 5
220 = 22x
x = 10

The domain is 10.



Question #2

Part A:

(2,255)
(5,480)

Standard form is Ax + By = C

\sf Slope = \frac{y_2-y_1}{x_2-x_1} = \frac{480-225}{5-2} = \frac{255}{3} = \boxed{85}

Let's plug this into this form first:
y - y_1 = m(x-x_1)\\\\y -225 = 85(x-2)\\\\y - 225 = 85x - 170\\\\y = 85x + 55

Now, let's make it into Standard Form.
y = 85x + 55\\\\y - 85x + 55\\\\ -85x + y = 55\\\\ -1(-85x +y) = -1(55)\\\\\boxed{85x - y = -55}
What, which is in the box, is your final answer. :)

Part B:
Function notation simply means replacing y with f(x).
We had y = 85x + 55
So your answer is:
\boxed{f(x) = 85x + 55}

Part C:
Using the final answer which we got in Part A, we would know that the y-intercept is (0,55) and the x-intercept is (-55/85, 0). We would plot these 2 points, and then draw a line between them. :)
5 0
3 years ago
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