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vova2212 [387]
3 years ago
8

Kuri spent a total of $68 on trading cards. His collection contains two types of cards. A pack of trading card A $4 and a pack o

f trading card b cost $7. HOW many packs of each trading card were purchased if the total number of packs is 11?​
Mathematics
2 answers:
masya89 [10]3 years ago
8 0

Answer:

8 of Card B and 3 of card A. Hope this helps

inysia [295]3 years ago
8 0

Answer:

Kuri purchased 3 packs of trading card A, and 8 packs of trading card B.

Step-by-step explanation:

1. First name the variables:

a = number of packs of trading card A

b = number of pack of trading card B

2. As a pack of trading card A costs $4, a pack of trading card b costs $7 and As Kuri spent a total of %68 on trading cards, the first equation is:

4a+7b=68 (Eq.1)

3. As Kuri purchased a total number of 11 packs, the second equation is:

a+b=11 (Eq.2)

4. Solve Eq.2 for a:

a+b=11\\\\a=11-b (Eq.3)

5. Replace Eq.3 in Eq.1 and solve por b:

4(11-b)+7b=68\\\\44-4b+7b=68\\\\-4b+7b=68-44\\\\3b=24\\\\b=\frac{24}{3}\\\\b=8

6. Replace the value of b in Eq.3:

a=11-8\\\\a=3

Therefore Kuri purchased 3 packs of trading card A, and 8 packs of trading card B.

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Let f and g be differentiable functions such that f(1) = 2, f'(1) = 3, f'(2) = -4, g(1) = 2, g'(1) = -3, g'(2) = 5. If h(x) = f
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Step-by-step explanation:

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Answer:

1)   68

    / \

 4     17

  /\

2  2

68=2*2*17

2)  104

   /      \

 4      26

  /\       /\

2  2   2   13

104=2*2*2*13

3) 78

    /\

 2    39

        /\

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4) 225

    /\

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  /\    /\

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225=3*3*5*5

Second Part:

1)  45

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       /\

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   2   35

          /\

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3)  54

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   /\    /\

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54=3*3*2*3

4)  126

      /\

    3   42

          /\

         3  14

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126=3*3*7*2

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