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4 years ago

Round 602813 to the nearest 10,000

Mathematics

2 answers:

likoan [24]4 years ago

6 0

600000 because you round to 0

svp [43]4 years ago

4 0

Answer:

60,000

Step-by-step explanation:

2813 rounds to 60,000 not 61,000

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There are (10^8)^2 ⋅ 10^0 candies in a store. What is the total number of candies in the store?

Vaselesa [24]

The answer would be the 3rd one, 10 to the power of 16 (10^16).

This is because you multiply the 2 powers (2 and 8) to get 16. When there is one power within a set of parenthesis and one power on the outside the parenthesis. Since there is a 10 to the 0 power (10^0) you add this power to 16 since it is multiplying integers with exponents. Thus getting 10^16 as an answer.

I hope this helps!

6 0

3 years ago

The equation of the function is Y=4x+5.Find the value of y when<br> x=3<br> x=-2

natita [175]

The equation of the function is y = 4x + 5. Find the value of y when

x = 3

x = -2

<h3>Given:-</h3>

y = 4x + 5 [Equation]

The value of y when x = 3 , x = -2

<h2>Solution:-</h2>

y = 4x + 5 [Given equation]

$\therefore$ When x = 3 ,

y = 4 × 3 + 5 [Value of x is 3]

y = 12 + 5

<h3>y = 17 [Answer]</h3>

Again, when x = -2 ,

y = 4 × (-2) + 5 [Value of x is -2]

y = -8 + 5

<h3>y = -3 [Answer]</h3>

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3 years ago

Abby and zach made cookies. They put 3 chips on each 5 cookies.

snow_lady [41]

If your asking how many chips there are in total... it would be 15

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3 years ago

Read 2 more answers

Find the sum of the finite geometric series. 4 20 100 ... 312,500 the sum of the geometric series is .

AnnZ [28]

What is the 9th term of the geometric sequence 4, -20, 100, ...
<span>First term, a = 4 </span>
<span>common ratio, r = –20 / 4 = –5 </span>
<span>..... ..... ..... ..... = 100 / –20 = –5 </span>
<span>9th term = 4 ( –5 ) ^ ( 9 - 1 ) </span>
<span>..... ...... = 4 ( –5 ) ^ 8 </span>
<span>..... ...... = 4 ( 390,625 ) </span>
<span>..... ...... = 1,562,500 </span>

5 0

3 years ago

A simple random sample of size nequals40 is drawn from a population. The sample mean is found to be 103.9, and the sample stand

yan [13]

Answer:

There is enough evidence to support the claim that the population mean is greater than 100

Step-by-step explanation:

<u>Step 1</u>: We state the hypothesis and identify the claim

$H_0:\mu=100$ and $H_1:\mu \:>\:100$ (claim)

<u>Step 2</u>: Calculate the test value.

$t=\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$

$\implies t=\frac{103.9-100}{\frac{21.9}{\sqrt{40} } }=1.1263$

<u>Step 3</u>: Find the P-value. The p-value obtained from a calculator is using d.f=39 and test-value 1.126 is 0.134

<u>Step 4</u>: We fail to reject the null hypothesis since P-value is greater that the alpha level. (0.134>0.05).

<u>Step 5</u>: There is enough evidence to support the claim that the population mean is greater than 100.

<u>Alternatively</u>: We could also calculate the critical value to obtain +1.685 for $\alpha=0.05$ and d.f=39 and compare to the test-value:

The critical value (1.685>1.126) falls in the non-rejection region. See attachment.

NB: The t- distribution must be used because the population standard deviation is not known.

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4 years ago