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2 years ago

The equation of the function is Y=4x+5.Find the value of y when x=3 x=-2

Mathematics

1 answer:

natita [175]2 years ago

8 0

The equation of the function is y = 4x + 5. Find the value of y when

x = 3

x = -2

<h3>Given:-</h3>

y = 4x + 5 [Equation]

The value of y when x = 3 , x = -2

<h2>Solution:-</h2>

y = 4x + 5 [Given equation]

$\therefore$ When x = 3 ,

y = 4 × 3 + 5 [Value of x is 3]

y = 12 + 5

<h3>y = 17 [Answer]</h3>

Again, when x = -2 ,

y = 4 × (-2) + 5 [Value of x is -2]

y = -8 + 5

<h3>y = -3 [Answer]</h3>

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Please answer correctly !!!!!!!!!!!!!! Will Mark Brianliest !!!!!!!!!!!!!!!!!!!

alexgriva [62]

Answer:

x = 30

Step-by-step explanation:

well from the theorem we have

$\frac{15}{3}=\frac{x}{6}$

yes i know you could say that the right way is

$\frac{3}{15}=\frac{6}{x}$

well if you notice they are the same only that in my way the x is in the numerator which means it will be far easier to know it's value :)

$\frac{15}{3}=\frac{x}{6}\\\\5=\frac{x}{6}\\\\6[5]=6[\frac{x}{6}]\\\\30=x$

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Using the Vertical Line Test<br> Which graph does not represent a function?

Nadusha1986 [10]

Using the Vertical Line Test, the graph does not represent a function is ellipse, the third graph.

<h3>What is vertical line test?</h3>

The vertical line test is a graphical method of determining whether a curve in the plane represents the graph of a function. It is done by visually examining the number of intersections of the curve with vertical lines.

Any vertical line in the x y plane must intersect the graph of a function at most once.

In the given graphs, the graph of a function intersects the y axis twice. So, it is not a function.

From the given graphs, the third graph which is of ellipse crosses the vertical line twice.

Thus, the graph does not represent a function is ellipse.

Learn more about vertical line test.

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1 year ago

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<h2>Question:- Area of the given diagram</h2>

<h2>Answer :- </h2>

Divide the diagram as shown in attachment.

Now first calculate the area of the rectangle having side 1 and 12

So area = length ×breadth

Area = 1× 12 = 12 unit²

Now find the Area of the remaining triangle with sides 12,13,5 units

$Area = \frac{1}{2} \times base \times height \:$

Now put the value as -> base= 5 and height= 12

$Area = \frac{1}{2} \times base \times height \: \\ Area = \frac{1}{2} \times 5 \times 12 \\ Area = \frac{1}{ \cancel2} \times 5 \times \cancel{12}^{ \: \: 6} \\ Area = 5 \times 6 \\ Area = 30 \: units^{2}$

Now add both areas for your answer

$Area{ \tiny{1}} = 12 {units}^{2} \\ Area{ \tiny2} = 30 {units}^{2} \\ Area{ \tiny{total}} = Area{ \tiny{1}} + Area{ \tiny{2}} \\ Area{ \tiny{total}} = 12 + 30 = 42 {units}^{2}$

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