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Nadusha1986 [10]
3 years ago
15

A cell is in a equilibrium with its surrounding at 30 degrees Celsius. The molarity of surrounding sucrose solution is 0.5m. Cal

culate the solute potential of the surrounding solution
Biology
1 answer:
Travka [436]3 years ago
7 0

Solute potential of a solution is calculated using the formula,

Ψ_{s}=-(iCRT)

Where,

Ψ_{s}is the solute potential of the solution,

<em>i</em> is the degree to which the solute ionizes(ionization constant) in solution = 1, as sucrose is a nonelectrolyte.

C is the concentration of the solution in molarity = 0.5 M

R is the gas constant or the pressure constant = 0.0831 L.bar/(mol.K)

T is the temperature in Kelvin scale = 30^{0}+273 =303 K

Calculating the solute potential of the surrounding sucrose solution:

Ψ_{s}=-(iCRT)

              = -(1 * 0.5 M * (0.0831 L.bar/(mol.K))* 303 K)

              = 12.6 bar

Therefore, the solute potential of the surrounding solution is 12.6 bar

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