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horrorfan [7]
3 years ago
12

A farmer caught some wild pigs to use as founders for a domestic herd. The farmer wants all of her pigs to have one distinctive

color. Most of the wild pigs are brown, but she catches a few with red hair and a few with black hair. The farmer plans to breed either the black-haired or the red-haired pigs to establish a pure-breeding herd (eliminating all other colors). Black hair (B) is dominant over brown (W). Black (B) and brown (W) are dominant over red (R). If the farmer wants her whole herd to reach its new color in as few generations as possible, should she breed for red-haired pigs, or should she breed for black-haired pigs? Why?
Mathematics
1 answer:
nikdorinn [45]3 years ago
8 0

Answer: Breed for black-haired pigs

Step-by-step explanation:

Now according to the statement, the farmer catches  wild pigs and mostly are brown.

Since black hair is dominant over brown and also black and brown are dominant over red,  this implies that red is the least dominant color meaning if breeding occurs, there would be less chance of getting red colored pigs.

She wants to breed either black or red haired pigs and since black is more dominant so she should breed the black ones with the brown ones or with themselves so she would eventually get pure-breeding herd i.e. of black color.

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Step-by-step explanation:

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3 years ago
6. A coupon offers $1.00 off the 16-ounce size. Which size is the better<br><br> buy then?
svlad2 [7]

Answer:

Both sizes are better because they cost Same.

Step-by-step explanation:

Consider the provided information.

A coupon offers $1.00 off the 16

            Quantity     Price

Pint           16           $3.98

Quart        32           $5.98

If he gets $1 off for the 16-ounce size. The price will be:

3.98-1=2.98

He needs to pay $2.98 for 16-ounce pint.

Now find which one is better by calculating the unit rate.

\frac{Cost}{weight}=\frac{2.98 }{16}\approx0.186

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\frac{Cost}{weight}=\frac{5.98}{32}\approx0.186

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What is an equation of the line that passes through the points (-4, -1)(−4,−1) and (2, 8)(2,8)?
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Answer:

y = 3 /2 x + 5

Step-by-step explanation:

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ANSWER ALL 5 PARTS.
N76 [4]
A function f from a set A to a set B is defined as a relation that assings to each element  x in the set A exactly one element y in the set B. The set A is called the domain of the function while the set B is the range. So we have five statements and need to find some functions. Melissa decides to reserve a patch in her vegetable garden for growing bell peppers. If each side of the tomato patch is x feet, then we have a square patch as shown in the Figure below.

1.a) Write the function Wa(x) representing the width of the bell pepper patch.

We know that she wants its width to be half the width of the tomato patch. Let x be the width of the tomato patch, then the function that matches this statement is:

\boxed{Wa(x)=\frac{x}{2}}

1.b) Write the function La(x) representing the length of the bell pepper patch.

In this case Melissa wants <span>its length to exceed the length of the tomato patch by 2 feet. To do this we enlarge the length of the tomato patch 2 feet. Therefore the function is the following:

</span>\boxed{La(x)=x+2}
<span>
2. Ar</span>ea of the bell pepper patch in terms of x.

Given that the bell pepper patch is a rectangle, then t<span>he area of a rectangle is the product of the length and width. So:

</span>A=(\frac{x}{2})(x+2) \\ \\ \therefore \boxed{A=\frac{x(x+2)}{2}}
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3. C</span><span>ombined area of the tomato patch and the bell pepper patch.

This function is the sum of both the area of the tomato patch and the bell pepper patch. So:

</span>Aar(x)=x^{2}+\frac{x(x+2)}{2} \rightarrow Aar(x)=x^{2}+ \frac{x^{2}}{2}+x \rightarrow Aar(x)=\frac{3x^{2}}{2}+x \\ \\ \therefore \boxed{Aar(x)=\frac{x(3x+2)}{2}}
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</span>Aa(x)=2(x-\frac{x}{2}) \rightarrow Aa(x)=x

5. 
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Given that <span>Melissa wants the area of the bell pepper patch to be 31.5 square feet, then it is true that:

</span>31.5=\frac{x(x+2)}{2} \rightarrow x^{2}+2x-64=0 \\ \\ solving \ for \ x: \\ x=7.06
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Therefore the area of the remaining space is:

</span>\boxed{Aa(7.06)=7.06ft^{2}}

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3 years ago
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