How many solutions does the following system of equations have
1 answer:
Answer:
Step-by-step explanation:
The two equations are
......(1)
2y = ......(2)
Equation (2) can be written as:
y =
Now these two equations represent a pair of parallel lines.
The equations of any two parallel line differ only by a constant.
Since, these are equations of parallel lines, they don't intersect. If they don't intersect they cannot have solutions.
⇒ The given system of equations has zero solutions.
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Answer:
(a) The probability that a randomly selected alumnus would say their experience surpassed expectations is 0.05.
(b) The probability that a randomly selected alumnus would say their experience met or surpassed expectations is 0.67.
Step-by-step explanation:
Let's denote the events as follows:
<em>A</em> = Fell short of expectations
<em>B</em> = Met expectations
<em>C</em> = Surpassed expectations
<em>N</em> = no response
<u>Given:</u>
P (N) = 0.04
P (A) = 0.26
P (B) = 0.65
(a)
Compute the probability that a randomly selected alumnus would say their experience surpassed expectations as follows:
Thus, the probability that a randomly selected alumnus would say their experience surpassed expectations is 0.05.
(b)
The response of all individuals are independent.
Compute the probability that a randomly selected alumnus would say their experience met or surpassed expectations as follows:
Thus, the probability that a randomly selected alumnus would say their experience met or surpassed expectations is 0.67.