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Juli2301 [7.4K]
4 years ago
6

Find the ARE of the figure

Mathematics
1 answer:
Tresset [83]4 years ago
5 0
First, break up the shapes into parts. The first one you see is 7 by 4 rectangle on the top.
A=l*w
A=7*4
A=28 for the rectangle, your not done
Now the triangle to the left
A=l*w/2
A=19*10/2
A=95
Now all you got left is the trapezoid, which area's formula is:
A=(b∧1+b∧2*h)/2
A=9+19*8/2
A=112.
Now you have the area for three of the figures, add them up:
112+95+28=235
So in total, the area of this figure is 235 cm^2
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When 8 is added to the number that is produced by doubling the number x, the result is equal to 8 times the number that is 5 les
ollegr [7]

Answer:

8

Step-by-step explanation:

Number = 2x

Therefore, 2x + 8 = 8(x - 5)

2x + 8 = 8x - 40

6x = 48

<u>x</u><u> </u><u>=</u><u> </u><u>8</u>

5 0
3 years ago
Rewrite the equation below to express the cost (c) as a function of miles (m). The charge for a rental car is $20 plus $0.05 per
Alja [10]
The answer is 
c(m) = $20 + $0.05m
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3 years ago
Irina has 6 tubs of yogurt she wants to scoop it all into bowls each bowl holds 1/4 tub of yogurt which division equation can be
elena55 [62]
In order to find the answer, you can use-

1/4x=6

In order to get the answer, you multiply 6 by the denominator. 

6x4=24

Then, you'd divide the solution of that part by the numerator.

24 divided by 1 equals 24.


Therefore, the final answer would be 24.


7 0
4 years ago
Read 2 more answers
Help!!!
Murljashka [212]

Answer:

mean=86+72+16+42+16+55+16+12+91+55/2

mean=230.5

mode=16-unimodal

median the middle value but in the first arrange in ascending order.

12,16,42,55,72,86 and 91

median=55

hope it helps!

6 0
2 years ago
Find the differential coefficient of <br><img src="https://tex.z-dn.net/?f=e%5E%7B2x%7D%281%2BLnx%29" id="TexFormula1" title="e^
Gemiola [76]

Answer:

\rm \displaystyle y' =   2 {e}^{2x}   +    \frac{1}{x}  {e}^{2x}  + 2 \ln(x) {e}^{2x}

Step-by-step explanation:

we would like to figure out the differential coefficient of e^{2x}(1+\ln(x))

remember that,

the differential coefficient of a function y is what is now called its derivative y', therefore let,

\displaystyle y =  {e}^{2x}  \cdot (1 +   \ln(x) )

to do so distribute:

\displaystyle y =  {e}^{2x}  +   \ln(x)  \cdot  {e}^{2x}

take derivative in both sides which yields:

\displaystyle y' =  \frac{d}{dx} ( {e}^{2x}  +   \ln(x)  \cdot  {e}^{2x} )

by sum derivation rule we acquire:

\rm \displaystyle y' =  \frac{d}{dx}  {e}^{2x}  +  \frac{d}{dx}   \ln(x)  \cdot  {e}^{2x}

Part-A: differentiating $e^{2x}$

\displaystyle \frac{d}{dx}  {e}^{2x}

the rule of composite function derivation is given by:

\rm\displaystyle  \frac{d}{dx} f(g(x)) =  \frac{d}{dg} f(g(x)) \times  \frac{d}{dx} g(x)

so let g(x) [2x] be u and transform it:

\displaystyle \frac{d}{du}  {e}^{u}  \cdot \frac{d}{dx} 2x

differentiate:

\displaystyle   {e}^{u}  \cdot 2

substitute back:

\displaystyle    \boxed{2{e}^{2x}  }

Part-B: differentiating ln(x)•e^2x

Product rule of differentiating is given by:

\displaystyle  \frac{d}{dx} f(x) \cdot g(x) = f'(x)g(x) + f(x)g'(x)

let

  • f(x) \implies   \ln(x)
  • g(x) \implies    {e}^{2x}

substitute

\rm\displaystyle  \frac{d}{dx}  \ln(x)  \cdot  {e}^{2x}  =  \frac{d}{dx}( \ln(x) ) {e}^{2x}  +  \ln(x) \frac{d}{dx}  {e}^{2x}

differentiate:

\rm\displaystyle  \frac{d}{dx}  \ln(x)  \cdot  {e}^{2x}  =   \boxed{\frac{1}{x} {e}^{2x}  +  2\ln(x)  {e}^{2x} }

Final part:

substitute what we got:

\rm \displaystyle y' =   \boxed{2 {e}^{2x}   +    \frac{1}{x}  {e}^{2x}  + 2 \ln(x) {e}^{2x} }

and we're done!

6 0
3 years ago
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