Answer: provided in the explanation section
Explanation:
Given that:
Assume D(k) =║ true it is [1 : : : k] is valid sequence words or false otherwise
now the sub problem s[1 : : : k] is a valid sequence of words IFF s[1 : : : 1] is a valid sequence of words and s[ 1 + 1 : : : k] is valid word.
So, from here we have that D(k) is given by the following recorance relation:
D(k) = ║ false maximum (d[l]∧DICT(s[1 + 1 : : : k]) otherwise
Algorithm:
Valid sentence (s,k)
D [1 : : : k] ∦ array of boolean variable.
for a ← 1 to m
do ;
d(0) ← false
for b ← 0 to a - j
for b ← 0 to a - j
do;
if D[b] ∧ DICT s([b + 1 : : : a])
d (a) ← True
(b). Algorithm Output
if D[k] = = True
stack = temp stack ∦stack is used to print the strings in order
c = k
while C > 0
stack push (s [w(c)] : : : C] // w(p) is the position in s[1 : : : k] of the valid world at // position c
P = W (p) - 1
output stack
= 0 =
cheers i hope this helps !!!
Answer:
peripheral device network connection
A virus or malware appearing/pretending to be a legitimate program is called a Trojan.
Text = “ I really like owls. Did you know that an owls eyes are more than twice as big as the eyes of other birds of comparable weight? And that when an owl partially closes its eyes during the day, it is just blocking out light? Sometimes I wish I could be an owl.
word = ‘owl’
texts = text.lower()
owlist = list(texts.split())
count = text.count(word)
num = [owlist, count] #num has no meaning just random var
print(num)
Alter in anyway you want so that you can succeed. ✌
