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sergejj [24]
3 years ago
9

Given m||n, find the value of x. Pleaseeeeee help geometry

Mathematics
1 answer:
sweet [91]3 years ago
6 0

Answer:

21°

Step-by-step explanation:

A line is 180 degrees.

Subtract 159 from 180 and you get the answer.

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Ospreys are birds that catch and eat fish. An osprey dived from a height of 36 feet above the surface of a lake to a
nikitadnepr [17]

Answer:

C

Step-by-step explanation: 36 is the height. Minus 4 is 32. So ye...

7 0
3 years ago
Can someone help pleaSE
aev [14]

Answer:

The correct answer is A) x = 1/4y^2

Step-by-step explanation:

Because the parabola opens to the side, we know that this is an x = equation. This allows us to eliminate both C and D.

Then we can determine that A is the correct answer due to the fact that it opens to the right. Negative lead coefficients always open to the left, so it could not be B

5 0
3 years ago
Help with the first section and second please. Also add explanation, or step by step. Thanks!
shepuryov [24]
<h3>1)</h3>

• 6x -2(x -5) = -2 . . . . given

• 6x -2x +10 = -2 . . . . X Cameron errored here. When multiplying -2 by -5, the result is 10, not -10.

• 4x +10 = -2 . . . . . . x terms are correctly collected

• 4x +10 -10 = -2 -10 . . . . add the opposite of the constant on the left

• 4x/4 = -12/4 . . . . divide by the x-coefficient

• x = -3 . . . . . . . . . . simplify

<h3>2)</h3>

• 11x -10 = -34 . . . . combine like terms

• 11x -10 +10 = 34 +10 . . . . addition property of equality

• 11x = 44 . . . . . . . . simplify

• 11x/11 = 44/11 . . . division property of equality

• x = 4 . . . . . . . . . . . simplify

7 0
3 years ago
The graph below shows the average Valentine’s Day spending between 2003 and 2012
Lapatulllka [165]
The average rate of change of a graph between two intervals is given by the difference in value of the values on the graph of the two interval divided by the difference between the two intervals.

Part A.

From the graph the average Valentine's day spending in 2005 is 98 while the average Valentine's day spending in 2007 is 120.

The average rate of change in spending between 2005 and 2007 is given by

\frac{120-98}{2007-2005} = \frac{22}{2} =\$11/year



Part B

From the graph the average Valentine's day spending in 2004 is 100 while the average Valentine's day spending in 2010 is 103.

The average rate of change in spending between 2004 and 2010 is given by

\frac{103-100}{2010-2004} = \frac{3}{6} =\$0.5/year



Part C:

From the graph the average Valentine's day spending in 2009 is 102 while the average Valentine's day spending in 2010 is 103.

The average rate of change in spending between 2009 and 2010 is given by

\frac{103-102}{2010-2009} = \$1/year

7 0
3 years ago
You are to give an injection of a drug. The dosage is 0.4 mg per kilogram of bod The concentration of the drug in vial is listed
kipiarov [429]

Answer:

You inject 60.9628 milliliters of dosage

Step-by-step explanation:

1 pound = 0.453592kg,

Patient's weight in pounds = 168

Patient's weight in kg = 76.2035  kg

Now we are given that The dosage is 0.4 mg per kilogram of bod

So, dosage = 0.4 \times 76.2035 mg = 30.4814 mg

1 microgram = 0.001 mg

Concentration of drug = 500 micrograms/ml = 500 * 0.001 mg/ml = 0.5 mg/ml

Now we are supposed to find How many milliliters (= cc) are you to inject?

So,milliliters of dosage required to inject = \frac{30.4814}{0.5} = 60.9628

Hence you inject 60.9628 milliliters of dosage

7 0
3 years ago
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