Answer:
C
Step-by-step explanation: 36 is the height. Minus 4 is 32. So ye...
Answer:
The correct answer is A) x = 1/4y^2
Step-by-step explanation:
Because the parabola opens to the side, we know that this is an x = equation. This allows us to eliminate both C and D.
Then we can determine that A is the correct answer due to the fact that it opens to the right. Negative lead coefficients always open to the left, so it could not be B
<h3>
1)</h3>
• 6x -2(x -5) = -2 . . . . given
• 6x -2x +10 = -2 . . . . X Cameron errored here. When multiplying -2 by -5, the result is 10, not -10.
• 4x +10 = -2 . . . . . . x terms are correctly collected
• 4x +10 -10 = -2 -10 . . . . add the opposite of the constant on the left
• 4x/4 = -12/4 . . . . divide by the x-coefficient
• x = -3 . . . . . . . . . . simplify
<h3>2)</h3>
• 11x -10 = -34 . . . . combine like terms
• 11x -10 +10 = 34 +10 . . . . addition property of equality
• 11x = 44 . . . . . . . . simplify
• 11x/11 = 44/11 . . . division property of equality
• x = 4 . . . . . . . . . . . simplify
The average rate of change of a graph between two intervals is given by the difference in value of the values on the graph of the two interval divided by the difference between the two intervals.
Part A.
From the graph the average Valentine's day spending in 2005 is 98 while the average Valentine's day spending in 2007 is 120.
The average rate of change in spending between 2005 and 2007 is given by

Part B
From the graph the average Valentine's day spending in 2004 is 100 while the average Valentine's day spending in 2010 is 103.
The average rate of change in spending between 2004 and 2010 is given by

Part C:
From the graph the average Valentine's day spending in 2009 is 102 while the average Valentine's day spending in 2010 is 103.
The average rate of change in spending between 2009 and 2010 is given by
Answer:
You inject 60.9628 milliliters of dosage
Step-by-step explanation:
1 pound = 0.453592kg,
Patient's weight in pounds = 168
Patient's weight in kg = 
Now we are given that The dosage is 0.4 mg per kilogram of bod
So, dosage = 
1 microgram = 0.001 mg
Concentration of drug = 
Now we are supposed to find How many milliliters (= cc) are you to inject?
So,milliliters of dosage required to inject = 
Hence you inject 60.9628 milliliters of dosage