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3 years ago

10

a model doll house is 3.25 feet long. the real house is 30 yards long. what is the unit rate that describes the relationship of

the real house to the model doll house?

1 answer:

DENIUS [597]3 years ago

3 0

Answer:

27.7

Step-by-step explanation:

1 yard = 3 feet

30 yards x 3 feet = 90 feet

90/3.25 = 27.7

You might be interested in

Given that -6,-6 is on the graph of f x find the corresponding point for the function f(3/4x)

Liono4ka [1.6K]

Answer:

The corresponding point is <em>(-8, -6).</em>

Step-by-step explanation:

Given that

(-6,-6) lies on the graph of $f(x)$

A function is represented in the form:

$y = f(x)$

i.e. (-6,-6) means value of x = -6 is put and value y came out as -6.

$f(-6) = -6$

Now, we have to find the corresponding point on $f(\frac{3}{4}x)$ .

We know the value of $f(-6)$

Let us find the value of x where $\frac{3}{4}x$ becomes equal to -6

$\dfrac{3}{4}x=-6\\\Rightarrow 3x=-24\\ \Rightarrow x =-8$

So, let us put value of $x = -8$ in $f(\frac{3}{4}x)$ :

$f(\frac{3}{4}\times (-8))\\\Rightarrow f(3\times (-2))\\\Rightarrow f(-6) = -6$ (as per given statement)

So, the corresponding point is <em>(-8, -6).</em>

4 0

3 years ago

andrew11 [14]

Answer:

A

Step-by-step explanation:

A. because the line of best fit has to be at best fit between the points so is a good approximation of where all the points are heading when you try to predict something.

8 0

3 years ago

The area of a rectangular ceiling tile is 756 square inches. The perimeter is 114 inches. What are the dimensions of the tile?

kogti [31]

Here we need to use what we know about rectangles to make a system of equations.

By solving that system we found that the tile has a length of 36 inches and a width of 21 inches.

Remember that for a rectangle of length L and width W, the perimeter is:

P = 2*(L + W)

And the area is:

A = W*L

Here we know that the perimeter is 114 inches, then we can write:

114in = 2*(L + W)

We also know that the area is 756 in^2, then we can write:

756 in^2 = L*W

So we found two equations, which means that we have a system of two equations with two variables:

114in = 2*(L + W)

756 in^2 = L*W

To solve this, the first step is to isolate one of the variables in one of the equations, we can isolate L in the first equation:

114in = 2*(L + W)

114in/2 = (L + W)

57in = L + W

57in - W = L

Now that we have an expression equivalent to L, we can replace it in the other equation to get:

756 in^2 = L*W

756 in^2 = (57in - W)*W

Now we can solve this for W.

756 in^2 = W*57in - W^2

W^2 - W*57in + 756 in^2 = 0

The solutions are given by the Bhaskara's formula:

$W = \frac{57in \pm \sqrt{(-57in)^2 - 4*1*(756in^2)} }{2*1} = \frac{57in \pm 15in}{2}$

Then the two possible values of the width will be:

W = (57in + 15in)/2 = 36 in

W = (57in - 15in)/2 = 21 in

Suppose that we choose the second solution, W = 21in

Now using the equation 57in - W = L we can find the value of L

L = 57in - W = 57in - 21in = 36in

L = 36in

Then we found that the tile has a length of 36 inches and a width of 21 inches.

If you want to learn more, you can read:

brainly.com/question/11137975

4 0

3 years ago

Think I know this but need help

AVprozaik [17]

E40435.29 = E404,000

E214729.08 = E215,000

E64968.75 = E650,000

E223589.99 = E224,000

E111111.11 = E110,000

Hope this helps , pleeease vote as brainliest!!

8 0

3 years ago

A random sample of 60 suspension helmets used by motorcycle riders and automobile race-car drivers was subjected to an impact te

pentagon [3]

Answer:

The 95% confidence interval on the true proportion of helmets of this type that would show damage from this test is (0.169, 0.397).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 60, \pi = \frac{17}{60} = 0.283$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.283 - 1.96\sqrt{\frac{0.283*0.717}{60}} = 0.169$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.283 + 1.96\sqrt{\frac{0.283*0.717}{60}} = 0.397$

The 95% confidence interval on the true proportion of helmets of this type that would show damage from this test is (0.169, 0.397).

6 0

3 years ago