Question

{x-3y=24} {3x+Y=12} Solve each of the following linear systems by eliminating

Answer 1

3x + y = 12 (multiply whole equation by 3)
x - 3y = 24

9x + 3y = 36
x - 3y = 24
10x = 60
x = 60 / 10
x = 6
puting the x value in 1st equation
3 (6) + y = 12
18 + y = 12
y = 12 - 18
y = -6

Answer x = 6
              y = -6