Assuming you pick 3 students at random, The probability that at least two plan on attending college is 84%.
<h3>Probability</h3>
Using Binomial Distribution
Given:
n = 3
p = 0.75
q = 1-0.95 = 0.25
Hence:
P[≥2] = P[2] + P[3]=(3c2 ×0.75²×0.25) + 0.75³
P[≥2] = P[2] + P[3]=0.421875+0.421875
P[≥2] = P[2] + P[3]=0.84375×100
P[≥2] = P[2] + P[3]=84% (Approximately)
Inconclusion the probability that at least two plan on attending college is 84%.
Learn more about probability here:brainly.com/question/24756209
Answer:
-440, -4440, -44440, -444440, -4444440
Step-by-step explanation:
First, let's find values for x which start is a -2 and end with a 2.
-22
-222
-2222
-22222
-222222
Now we can find the y value by multiplying each term by 20.
-22 --> -440
-222 --> -4440
-2222 --> -44440
-22222 --> -444440
-222222 --> -4444440
It says pdf loading so i can’t help sorry
14.29 * .0725 = 1.04
1.04 * 3 = 3.12
Answer:
False
Step-by-step explanation:
5 3/8 > 5 4/10
