Look at the picture the question is there

Mathematics

1 answer:

KonstantinChe [14]3 years ago

7 0

Answer:

1st answer

Step-by-step explanation:

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The thousand islands are located along the border between new york and canada. the adventure club wants to place a stone marker

Nikitich [7]

Using proportions, it is found that the number of islands that each member will have to visit is given by:

c. 19 islands.

<h3>What is a proportion?</h3>

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

In this problem, there are 684 islands, and 36 members, hence the number of islands per member is given by:

n = 684/36 = 19.

Which means that option c is correct.

More can be learned about proportions at brainly.com/question/24372153

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2 years ago

Given that x = 1, y = -2, z = 3, find the value of:

yarga [219]

You have to plug in the given numbers and perform each operation. Let me know if you have questions. The answers are circled.

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3 years ago

In a survey of adults who follow more than one sport, 30% listed football as their favorite sport. You survey 15 adults who foll

maxonik [38]

Answer: 0.5

Step-by-step explanation:

Binomial probability formula :-

$P(x)=^nC_x\ p^x(q)^{n-x}$ , where P(x) is the probability of getting success in x trials , n is the total trials and p is the probability of getting success in each trial.

Given : The probability that the adults follow more than one game = 0.30

Then , q= 1-p = 1-0.30=0.70

The number of adults surveyed : n= 15

Let X be represents the adults who follow more than one sport.

Then , the probability that fewer than 4 of them will say that football is their favorite sport,

$P(X\leq4)=P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)\\\\=^{15}C_{0}\ (0.30)^0(0.70)^{15}+^{15}C_{1}\ (0.30)^1(0.70)^{14}+^{15}C_{2}\ (0.30)^2(0.70)^{13}+^{15}C_{3}\ (0.30)^3(0.70)^{12}+^{15}C_{4}\ (0.30)^4(0.70)^{11}\\\\=(0.30)^0(0.70)^{15}+15(0.30)^1(0.70)^{14}+105(0.30)^2(0.70)^{13}+455(0.30)^3(0.70)^{12}+1365(0.30)^4(0.70)^{11}\\\\=0.515491059227\approx0.5$