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AleksandrR [38]
3 years ago
7

Look at the picture the question is there

Mathematics
1 answer:
KonstantinChe [14]3 years ago
7 0

Answer:

1st answer

Step-by-step explanation:

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Plsss if you can find x
Vikki [24]

Answer:

x=15

Step-by-step explanation:

4 0
2 years ago
Given: △ABC is equilateral. The radius of each circle is r. Find: AB
stich3 [128]

Answer:

2r (1 + √3)

Step-by-step explanation:

Circle O₁ is tangent to AB.  Let's call the point of intersection point D.  If we draw a radius from the center O₁ to D, we know this forms a right angle.

△ABC is an equilateral triangle, so we know m∠A = 60°.  If we draw a line from A to O₁, we know that bisects the angle, so m∠DAO₁ = 30°.

So △DAO₁ is a 30-60-90 triangle.  We can find the length AD:

AD = r √3

Now on the other side, circle O₃ is tangent to AB.  Let's call the point of intersection point E.  We know it's the same triangle we found earlier, so:

EB = r √3

And finally, we can draw a rectangle connecting O₁, O₃, E, and D.  The distance between O₁ and O₃ is 2r, so:

DE = 2r.

Therefore:

AB = r√3 + 2r + r√3

AB = 2r√3 + 2r

AB = 2r (1 + √3)

Here's a graph showing the steps.  Hopefully this helps, let me know if you have questions!

desmos.com/calculator/hgaonfzxsm

8 0
3 years ago
HELP PLEASE DUE DATE IS IN 30 MIN I DONT KNOW THE ANSWER I GIVE BRAINLIEST PLEASE THANK YOU
lesya [120]

Answer: (-1/2, 0)

Step-by-step explanation: A reflection across the y-axis would simply mirror the x coordinate, making it x=-1/2 instead of x=1/2

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2 years ago
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MAVERICK [17]
It's C



Good luck! ((((((:
5 0
3 years ago
If f(x) = ln(2), then limx--->2 (f(2)-f(x))/x-2
Blizzard [7]

Answer:

  • as written, -2
  • with denominator parentheses, 0
  • with f(x)=ln(x) and denominator parentheses, -1/2

Step-by-step explanation:

The problem as stated asks for the limit as x approaches 2 of (0/x) -2.

As written, the limit is (0/2) -2 = -2.

<u>Explanation</u>: f(x) is a constant, so the numerator is 0. The ratio 0/x -2 is defined as -2 everywhere except x=0. So, the value at x=2 is 0/2 -2 = -2.

__

If you mean (f(2) -f(x))/(x -2), that limit is the limit of 0/(x-2) = 0 as x approaches 2.

<u>Explanation</u>: f(x) is a constant, so the numerator is 0. The ratio 0/(x-2) is zero everywhere except at x=2. The left limit and right limit are both 0 as x approaches 2. Since these limits agree, the limit is said to be 0.

__

If you mean f(x) = ln(x) and you want the limit of (f(2) -f(x))/(x -2), that value will be -1/2.

<u>Explanation</u>: The value of the ratio is 0/0 at x=2, so we can find the limit using L'Hôpital's rule. Differentiating numerator and denominator, we have ...

  lim = (-1/x)/(1)

The value is -1/2 at x=2.

7 0
3 years ago
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