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eimsori [14]
3 years ago
14

Its coordinate plane plz help

Mathematics
1 answer:
Tpy6a [65]3 years ago
4 0
The distance is 6 units. You can figure this out by using the distance formula. :-)
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Help me on all please
nirvana33 [79]

Answer:

look at the rest

Step-by-step explanation:

1.)same line

2.)intersect

3.)parallel

4.)ordered pair

4 0
3 years ago
-1.5b = 24 what is the answer to b
zlopas [31]
-16b is the answer :)
3 0
3 years ago
Read 2 more answers
Write the first five terms of the arithmetic sequence. a1 = 9; d = -2
asambeis [7]

Answer:

nth term = 1 1/2n -1

Step-by-step explanation:

The arithmetic sequence formula is:

a n = a 1 + ( n – 1 ) d

Where: a n

is the nth term in the sequence

a 1

is the first term in the sequence

n

is the term you are solving for

d

is the common difference for any pair of consecutive numbers in the sequence.

First Term or  

n = 1 :

This is given in the problem.

a 1  =  9

Second Term or  

n = 2 :

Substitute  

2  for  n

in the formula and substitute the values from the problem giving:

a 2 = 9 + ( ( 2 – 1 ) × -2 )

a 2 = 9 + ( 1 × -2 )

a 2 = 9 +-2

a 2 = 7

Fifth Term or  n = 5 :

Substitute      in the formula and substitute the values from the problem giving:

a 5 = 9+ ( ( 5– 1 ) × -2 )

a 5 = 9 + ( 4 × -2 )

a 2 = 9 + -8

a 2 = 1  

Using this same process you should be able to determiner the

Third Term or  n = 3

: and Fourth Term or  n = 4 :

4 0
2 years ago
Given that f.x 3x-2 over x+1 g[x] x +5 evaluate f[-4] and gf [-2]
Jobisdone [24]

The value of f[ -4 ] and g°f[-2] are \frac{14}{3} and 13 respectively.

<h3>What is the value of f[-4] and g°f[-2]?</h3>

Given the function;

  • f(x) = \frac{3x-2}{x+1}
  • g(x)=x+5
  • f[ -4 ] = ?
  • g°f[ -2 ] = ?

For f[ -4 ], we substitute -4 for every variable x in the function.

f(x) = \frac{3x-2}{x+1}\\\\f(-4) = \frac{3(-4)-2}{(-4)+1}\\\\f(-4) = \frac{-12-2}{-4+1}\\\\f(-4) = \frac{-14}{-3}\\\\f(-4) = \frac{14}{3}

For g°f[-2]

g°f[-2] is expressed as g(f(-2))

g(\frac{3x-2}{x+1}) =  (\frac{3x-2}{x+1}) + 5\\\\g(\frac{3x-2}{x+1}) =  \frac{3x-2}{x+1} + \frac{5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{3x-2+5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{8x+3}{x+1}\\\\We\ substitute \ in \ [-2] \\\\g(\frac{3x-2}{x+1}) =  \frac{8(-2)+3}{(-2)+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{-16+3}{-2+1}\\\\g(\frac{3x-2}{x+1}) =  \frac{-13}{-1}\\\\g(\frac{3x-2}{x+1}) =  13

Therefore, the value of f[ -4 ] and g°f[-2] are \frac{14}{3} and 13 respectively.

Learn more about composite functions here: brainly.com/question/20379727

#SPJ1

6 0
2 years ago
NEED HELP QUICK !!!<br> Find the value of side X ?
tankabanditka [31]

a²+b²=x²

4²+3²= x²

16+9= x²

25= x²

V25= x

5= x

7 0
2 years ago
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