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kipiarov [429]
2 years ago
10

52:PLEASE HELP Find the slope of the line that passes through the points (8,2) and (9,7)

Mathematics
2 answers:
Katena32 [7]2 years ago
5 0

Answer:

5/1

Step-by-step explanation:it goes up 5 and over 1

topjm [15]2 years ago
4 0

Answer:

<h2>5</h2>

Solution,

Let the points be A and B

A ( 8 , 2 ) -----> (X1 , y1 )

B ( 9 , 7 ) -------> (x2 , y2)

Now,

Slope =\frac{y2 - y1}{x2 - x1}

=  \frac{7 - 2}{9 - 8}

= \frac{  5}{1}

= 5

Hope this helps..

Good luck on your assignment...

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Nataly_w [17]
1. f(x) = 1
2. f(x) = x
3. f(x) = 5 - x
4. f(x) = 3
8 0
3 years ago
g Suppose we have a simple random sample of 400 households drawn from a city with 40,000 households . A 95% confidence interval
kherson [118]

Answer:

gay

Suppose we have a simple random sample of 400 households drawn from a city with 40,000 households . A 95% confidence interval estimate for the population mean number of children per household is [1.1,2.3]. Given this, what is the lower confidence limit for the total number of children in the city

8 0
3 years ago
P: 2,012
OleMash [197]

El volumen <em>remanente</em> entre la esfera y el cubo es igual a 30.4897 centímetros cúbicos.

<h3>¿Cuál es el volumen remanente entre una caja cúbica vacía y una pelota?</h3>

En esta pregunta debemos encontrar el volumen <em>remanente</em> entre el espacio de una caja <em>cúbica</em> y una esfera introducida en el elemento anterior. El volumen <em>remanente</em> es igual a sustraer el volumen de la pelota del volumen de la caja.

Primero, se calcula los volúmenes del cubo y la esfera mediante las ecuaciones geométricas correspondientes:

Cubo

V = l³

V = (4 cm)³

V = 64 cm³

Esfera

V' = (4π / 3) · R³

V' = (4π / 3) · (2 cm)³

V' ≈ 33.5103 cm³

Segundo, determinamos la diferencia de volumen entre los dos elementos:

V'' = V - V'

V'' = 64 cm³ - 33.5103 cm³

V'' = 30.4897 cm³

El volumen <em>remanente</em> entre la esfera y el cubo es igual a 30.4897 centímetros cúbicos.

Para aprender más sobre volúmenes: brainly.com/question/23940577

#SPJ1

3 0
1 year ago
David found and factored out the GCF of the polynomial 80b4 – 32b2c3 + 48b4c. His work is below. GFC of 80, 32, and 48: 16 GCF o
BlackZzzverrR [31]

Answer: The correct statements are

The GCF of the coefficients is correct.

The variable c is not common to all terms, so a power of c should not have been factored out.

David applied the distributive property.

Step-by-step explanation:

GCF = Greatest common factor

1) GCF of coefficients : (80,32,48)

80 = 2 × 2 × 2 × 2 × 5

32 = 2 × 2 × 2 × 2 × 2

48 = 2 × 2 × 2 × 2 × 3

GCF of coefficients : (80,32,48) is 16.

2) GCF of variables :(b^4,b^2,b^4)

b^4= b × b × b × b

b^2 = b × b

b^4 =b × b × b × b

GCF of variables :(b^4,b^2,b^4) is b^2

3) GCF of c^3 and c: c is not the GCF of the polynomial. The variable c is not common to all terms, so a power of c should not have been factored out.

4) 80b^4-32b^2c^3+48b^4c

=16b^2(5b^2-2c^3+3b^2c)

David applied the distributive property.

7 0
2 years ago
Read 3 more answers
What is the solution set for this inequality?<br> -8x + 40&gt;-16
dolphi86 [110]

Answer:

x<7

Step-by-step explanation:

hope this helps :)

3 0
3 years ago
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