Answer:
N=5 key task decision start and end
Explanation:
Answer:
O(n²)
Explanation:
The worse case time complexity of insertion sort using binary search for positioning of data would be O(n²).
This is due to the fact that there are quite a number of series of swapping operations that are needed to handle each insertion.
Answer:
The "Value" variable contains the lowest value of array1 list.
Explanation:
- When the user passes the value on the array, then the above code is used to find the minimum value from the list of value which is passed by the user.
- The above array has the 25 sizes, so it will take only 25 value from the user, Then the loop will assume the first value as the minimum value and assign that value on the variable "value".
- Then all the other elements accessed by the for loop and compare with the value of Value variable if the array value is minimum, then that value is assigned on the variable value.
- Hence the minimum value of the list will be assigned on the variable value.
