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Soloha48 [4]
2 years ago
6

Assume that c is a char variable has been declared and already given a value. write an expression whose value is true if and onl

y if c is not what is called a whitespace character (that is a space or a tab or a newline-- none of which result in ink being printed on paper).
Computers and Technology
1 answer:
lara [203]2 years ago
7 0
Return isgraph(c));
////////////////

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I really need this done Thank you!!
Zepler [3.9K]

Answer:

10

Explanation:

the interval in the printed numbers is 10.

6 0
3 years ago
Define and test a function myRange. This function should behave like Python’s standard range function, with the required and opt
Reil [10]

Answer:

YOU DONT HAVE A QUESTION ITS A LONG STATEMENT

Explanation:

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3 years ago
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How to transfer bookmarks to new computer
Romashka-Z-Leto [24]

Explanation:

On your computer, open Chrome

.At the top right, click More

.Select Bookmarks Import Bookmarks and Settings

.Select the program that contains the bookmarks you'd like to import.Click Import.

Click Done

3 0
3 years ago
NAND is logically complete. Use only NAND gates to constructgate-level circuits that compute the
Drupady [299]

Answer:

Hi, for this exercise we have two laws to bear in mind:

Morgan's laws

NOT(А).NOT(В) = NOT(A) + NOT (B)

NOT(A) + NOT (B) = NOT(А).NOT(В)

And the table of the Nand

INPUT OUTPUT

A B A NAND B

0 0         1

0 1         1

1 0         1

1 1         0

Let's start!

a.

Input            OUTPUT

A       A     A NAND A

1         1             0

0        0            1

b.

Input            OUTPUT

A       B     (A NAND B ) NAND (A NAND B )

0         0            0

0         1            0

1          0             0

1          1             1

C.

Input            OUTPUT

A       B     (A NAND A ) NAND (B NAND B )

0        0           0

0        1             1

1         0            1

1          1            1

Explanation:

In the first one, we only need one input in this case A and comparing with the truth table we have the not gate

In the second case, we have to negate the AND an as we know how to build a not, we only have to make a nand in the two inputs (A, B) and the make another nand with that output.

In the third case we have that the OR is A + B and we know in base of the morgan's law that:

A + B = NOT(NOT(А).NOT(В))

So, we have to negate the two inputs and after make nand with the two inputs negated.

I hope it's help you.

3 0
3 years ago
Which of the following is a property of TCP?
Serggg [28]

Answer:

o best effort

Explanation:

beacuse it i think do

3 0
3 years ago
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