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d1i1m1o1n [39]
3 years ago
15

Give the conjugate acid for each compound below. co3^2-

Chemistry
1 answer:
DENIUS [597]3 years ago
7 0
A conjugate acid is a conjugate base with hydrogen ions attached to it. In this case, the conjugate base is the carbonate ion, CO₃⁻². This ion can have two hydrogen ions, so the conjugate acid is:

H₂CO₃

This compound is known as carbonic acid.
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For this reaction, 11.5 g nitrogen monoxide reacts with 9.91 g oxygen gas. nitrogen monoxide (g) + oxygen (g) nitrogen dioxide (
Artist 52 [7]

Answer : The mass of nitrogen dioxide is, 17.6 grams

The formula of limiting reagent is, NO

The mass of excess reagent remains is, 3.74 grams

Explanation : Given,

Mass of NO = 11.5 g

Mass of O_2 = 9.91 g

Molar mass of NO = 30 g/mol

Molar mass of O_2 = 32 g/mol

First we have to calculate the moles of NO and O_2.

\text{Moles of }NO=\frac{\text{Given mass }NO}{\text{Molar mass }NO}

\text{Moles of }NO=\frac{11.5g}{30g/mol}=0.383mol

and,

\text{Moles of }O_2=\frac{\text{Given mass }O_2}{\text{Molar mass }O_2}

\text{Moles of }O_2=\frac{9.91g}{32g/mol}=0.309mol

Now we have to calculate the limiting and excess reagent.

The balanced chemical equation is:

2NO(g)+O_2(g)\rightarrow 2NO_2(g)

From the balanced reaction we conclude that

As, 2 mole of NO react with 1 mole of O_2

So, 0.383 moles of NO react with \frac{0.383}{2}=0.192 moles of O_2

From this we conclude that, O_2 is an excess reagent because the given moles are greater than the required moles and NO is a limiting reagent and it limits the formation of product.

Moles of excess reagent remains = 0.309 - 0.192 = 0.117 mol

Now we have to calculate the mass of excess reagent remains.

\text{ Mass of excess reagent}=\text{ Moles of excess reagent}\times \text{ Molar mass of excess reagent}

Molar mass of O_2 = 32 g/mole

\text{ Mass of excess reagent}=(0.117moles)\times (32g/mole)=3.74g

Now we have to calculate the moles of NO_2

From the reaction, we conclude that

As, 2 mole of NO react to give 2 mole of NO_2

So, 0.383 mole of NO react to give 0.383 mole of NO_2

Now we have to calculate the mass of NO_2

\text{ Mass of }NO_2=\text{ Moles of }NO_2\times \text{ Molar mass of }NO_2

Molar mass of NO_2 = 46 g/mole

\text{ Mass of }NO_2=(0.383moles)\times (46g/mole)=17.6g

8 0
3 years ago
If the pressure, volume, and temperature of a gas are known, which can most likely be found by using the ideal gas law
Alenkasestr [34]

the ideal gas law equation is as follows

PV = nRT

where P - pressure

V - volume

n - number of moles

R - universal gas constant

T - temperature

so if the pressure, volume and temperature are already known

we are left with n and R

since R is the universal gas constant that has a known fixed value then R too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation


8 0
3 years ago
Read 2 more answers
the scientist found that 2 grams of hydrogen reacted completely with16 grams of oxygen what was the total mass of the water prod
MA_775_DIABLO [31]
Total mass of water = 2 +16 = <u>18g</u>

As mass needs to be conserved
7 0
3 years ago
How much energy is required to vaporize 0.5kg of water?
White raven [17]

Answer:

Explanation:

Vaporization Equation => Q = m·ΔHv

m = 0.5Kg water = 500g water

ΔHv = Heat of vaporization = 540 calories/gram

∴Q = 500g x 540cal/g = 270,000 calories x 4.184 joules/cal = 1,129,680 joules = 1130 Kilojoules (3 sig. figs.)

3 0
3 years ago
What 4 words make up the acronym for NASA.
Nonamiya [84]
If you mean what the abbreviation stands for, NASA means <span>National Aeronautics and Space Administration. Hope this helps!!</span>
5 0
3 years ago
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