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3 years ago

Give the conjugate acid for each compound below. co3^2-

1 answer:

7 0

A conjugate acid is a conjugate base with hydrogen ions attached to it. In this case, the conjugate base is the carbonate ion, CO₃⁻². This ion can have two hydrogen ions, so the conjugate acid is:

H₂CO₃

This compound is known as carbonic acid.

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Which compound does H2SO4 represent when in an aqueous solution?

solong [7]

H₂SO₄ represents Sulphuric acid or SO₄²⁻ ion when in aqueous as well as H⁺ and a little amount of HSO₄⁻ all of these ions can form in aqueous on dissolving H₂SO₄

4 0

3 years ago

Read 2 more answers

B. Organic sedimentary rock

Serga [27]

Answer:

A. Clastic sedimentary rocks

Explanation:

Chemical form = CaCO3

Clastic sedimentary rocks form from the accumulation and lithification of mechanical weathering debris. Examples include: breccia, conglomerate, sandstone, siltstone, and shale.

Hope this helps! :)

3 0

3 years ago

Anatom that has lewer neutrons than protons and more electrons than protons is

Ludmilka [50]

Answer:

a negative ion, and an isotope.

Explanation:

The perfect atom consists of an equal balance in all 3. If the neutrons are not even with the protons, it is an isotope since it is like another version of the so called (but not actually) 'perfect' atom. If there is more electrons, the charge is negative, making it an ion.

8 0

3 years ago

The process of breaking a complex substance down into smaller components is called

Tcecarenko [31]

Its called Hydrolysis where you break larger complex molecules into smaller ones

such as hydrolysing starch into its monomers

hope that helps

3 0

3 years ago

If 30.0 mL of Ca(OH)2 with an unknown concentration is neutralized by 40.0 mL of 0.175 M HCl, what is the concentration of the C

Over [174]

Answer:

Concentration of Ca(OH)₂:

0.117 M.

Explanation:

How many moles of HCl is consumed?

Note the unit of concentration: moles per liter solution.

$c(\text{HCl}) = 0.175\;\text{M} = 0.175\;\text{mol}\cdot\textbf{L}^{-1}$ .

Convert milliliters to liters.

$V(\text{HCl})=40.0\;\text{mL} = 0.0400\;\text{L}$ .

$n(\text{HCl}) = c(\text{HCl})\cdot V(\text{HCl})= 0.175\;\text{mol}\cdot\text{L}^{-1} \times 0.0400\;\text{L}= 7.00\times 10^{-3}\;\text{mol}$ .

How many moles of NaOH in the solution?

Refer to the equation. The coefficient in front of Ca(OH)₂ is 1. The coefficient in front of HCl is 2. In other words, it takes two moles of HCl to neutralize one mole of Ca(OH)₂. That $7.00\times 10^{-3}\;\text{mol}$ of HCl will neutralize only half that much Ca(OH)₂.

$\displaystyle n(\text{Ca}(\text{OH})_2)=\frac{1}{2}\;n(\text{HCl}) = 3.50\times 10^{-3}\;\text{mol}$ .

What's the concentration of the Ca(OH)₂ solution?

Concentration is the number of moles of solute per unit volume.

$\displaystyle c(\text{Ca}(\text{OH})_2) = \frac{n(\text{Ca}(\text{OH})_2)}{V(\text{Ca}(\text{OH})_2)} = \frac{3.50\times 10^{-3}\;\text{mol}}{0.0300\;\text{L}}=0.117\;\text{mol}\cdot\text{L}^{-1}$ .

3 0

2 years ago