Carbon burns in the presence of oxygen to give carbon dioxide. Which chemical equation describes this reaction?

Question: complete the mechanism for the below oxidation of an alkene with kmno4. draw the missing curved

iren2701 [21]

Mechanism for oxidation of alkene by KMnO₄ is provided in the attached image:

6 0

2 years ago

a particular application calls for N2 g with a density of 1.80 g/L at 32 degrees C what must be the pressure of the n2 g in mill

baherus [9]

Answer:

1223.38 mmHg

Explanation:

Using ideal gas equation as:

$PV=nRT$

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = $62.3637\text{ L.mmHg }mol^{-1}K^{-1}$

Also,

Moles = mass (m) / Molar mass (M)

Density (d) = Mass (m) / Volume (V)

So, the ideal gas equation can be written as:

$PM=dRT$

Given that:-

d = 1.80 g/L

Temperature = 32 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T = (32 + 273.15) K = 305.15 K

Molar mass of nitrogen gas = 28 g/mol

Applying the equation as:

P × 28 g/mol = 1.80 g/L × 62.3637 L.mmHg/K.mol × 305.15 K

⇒P = 1223.38 mmHg

1223.38 mmHg must be the pressure of the nitrogen gas.

5 0

3 years ago

Explain mitosis and meiosis in your own words.

LuckyWell [14K]

I always remembered the differences by Mitosis sounds like My Toes Is. Which means its body cells reproducing.
And Meiosis is My overies. Which is sex cells reproducing.

Mitosis - The body cell's nucleus makes a copy of its chromosomes. The Chromotids are then pulled to the poles of the cell and split in half, the cell then divides in half into two new cells. Each cell has one pair of chromosomes each.

Meiosis - The sex cells nucleus makes a copy of each chromosome same as before. But then the similar chromosomes group up and swap parts with each other. Making completely new chromosomes. They then split in half again, making two new cells with two different pairs of chromosomes. Which then split apart Once more creating 4 new cells (From the original one) Each with completely random chromosomes.

4 0

3 years ago

Calculate the mass of CO2 that can be produced if the reaction of 54.0 g of propane and sufficient oxygen has a 64.0% yield.

Oduvanchick [21]

Answer:

103.9 g

Explanation:

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

First we convert 54.0 g of propane (C₃H₈) into moles, using its molar mass:

54.0 g ÷ 44 g/mol = 1.23 mol C₃H₈

Then we convert 1.23 moles of C₃H₈ into moles of CO₂, using the stoichiometric coefficients:

1.23 mol C₃H₈ * $\frac{3molCO_2}{1molC_3H_8}$ = 3.69 mol CO₂

We convert 3.69 moles of CO₂ into grams, using its molar mass:

3.69 mol CO₂ * 44 g/mol = 162.36 g

And apply the given yield:

162.36 g * 64.0/100 = 103.9 g

7 0

2 years ago

Mass box A = 10 grams; Mass box B = 5 grams; Mass box C—made of one A and one B

eimsori [14]

2 boxes of A
Because C = A + B
2 of A = 20 grams
at the other hand we have 2 of B = 10
So 20 + 10 = 30 grams

3 0

3 years ago