Carbon burns in the presence of oxygen to give carbon dioxide. Which chemical equation describes this reaction?

s344n2d4d5 [400]

Answer: 6.2 grams of the sodium acetate can dissolve in 5 milliliters of water. if 124 grams of the sodium acetate dissolves in 100 milliliters of water, then 6.2 grams of the sodium acetate can dissolve in 5 milliliters of water.

4 0

2 years ago

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Hurry and Help for Brainlist

zalisa [80]

Ummm i think it’s solid

3 0

2 years ago

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Which of the following statements is TRUE? A. State functions do not depend on the path taken to arrive at a particular state. B

Serga [27]

Answer:

E. All of the above are true.

Explanation:

Which of the following statements is TRUE?

A. State functions do not depend on the path taken to arrive at a particular state. TRUE. State functions like enthalpy (ΔH) and internal energy (ΔE) do not depend on the trajectory, but on the initial and final state.

B. Energy is neither created nor destroyed, excluding nuclear reactions. TRUE. Only in nuclear reactions can energy (E) can be transformed in matter (m) and vice-versa according to Einstein equation: E = m . c² (c is the speed of light).

C. ΔHrx can be determined using constant pressure calorimetry. TRUE. The enthalpy of reaction is the heat involved at constant pressure.

D. ΔErx can be determined using constant volume calorimetry. TRUE. The internal energy of reaction is the heat involved at constant volume.

6 0

3 years ago

The K a of propanoic acid ( C 2 H 5 COOH ) is 1.34 × 10 − 5 . Calculate the pH of the solution and the concentrations of C 2 H 5

Zigmanuir [339]

Answer:

2.62.

Explanation:

Okay let us first write the parameters in the question in question above out. We are given the ka value of propanoic acid, C2H5COOH to be equals to 1.34 × 10^- 5. Also, we are given the value for the initial concentration of propanoic acid to be 0.441 M.

So, let us delve right into the solution to the question and we will be starting by writting the equation below;

C2H5COOH <--------> H^+ + C2H5COO^-.

Please note that this Reaction is a reversible Reaction.

Therefore, the basic things about acid is its great tendency to release Hydrogen ion in an aqeous solution.

So, we will be taken equation above and correspond it with the time and Concentration.

C2H5COOH <----> H^+ C2H5COO^-.

Initial concentration of the C2H5COOH = 0.441 M and the initial concentration of H^+ and C2H5COO^- are both zero.

So, after a time, t, concentration of C2H5COOH= 0.441 - x and at that time the concentration of H^+ and C2H5COO^- are both x and x respectively.

Hence, Ka = [C2H5COO^-] [H^+]/ C2H5COOH. -----------------------(**).

Therefore, slotting in the values from above into equation (**), we have;

1.34 × 10^-5 = [x] [x]/ [0.441 - x].

1.34 × 10^-5= x^2/ [0.441 - x].

x^2 = 1.34 × 10^-5(0.441) - 1.34 × 10^-5x.

x^2 + 1.34 × 10^-5x - 5.91× 10^-6.

x = 2.4×10^-3.

Hence, the concentration of the propanoic acid at time, t= 0.441 - 2.4 ×10^-3.

==> 0.44 M.

pH = -log [H^+].

Then, we have; pH= - log[2.4× 10^-3].

pH= 2.62.

4 0

2 years ago

How many kilojoules are released when 116 g of Cl2 reacts with silicon? Si(s)+2Cl2(g)→SiCl4(g)ΔH=−657kJ

alexandr402 [8]

Answer:- 537 kJ of heat is released.

Solution:- For the given equation, $\Delta H$ is -657 kJ and the coefficient of $Cl_2$ in the balanced equation is 2. It means 657 kJ of heat is released when 2 moles of chlorine are used. We need to calculate the heat released when 116 g of $Cl_2$ are used.

Grams of chlorine are converted to moles and then multiplied by the $\Delta H$ value and divided by the coefficient of chlorine and the set could be shown using dimensional analysis as:

$116gCl_2(\frac{1mol}{70.9g})(\frac{657kJ}{2mol})$

= 537.46 kJ

If we use the correct sig figs then it needs to be round off to three sig figs as the given grams of chlorine has only three sig figs. So, 537 kJ of heat is released.

6 0

2 years ago