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Fantom [35]
3 years ago
5

12. How are secondary sources of energy different from other energy resources?

Chemistry
1 answer:
Mkey [24]3 years ago
5 0

Answer:

A primary source of energy is a fossil fuel , nuclear fuel , wind or sunlight in an unconverted state . A secondary source of energy is created when a primary source of energy is burned or otherwise converted into a form , like electricity, that can be used for useful work.

Explanation:

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The equilibrium for the reaction between (ch3)2nh a weak base
nadezda [96]

The equilibrium for the dissolution of the weak base is ;(CH3)2NH(aq) + H2O(l) ⇄ (CH3)2NH3^+(aq) + OH^-(aq)

<h3>What is a weak base?</h3>

A weak base is one that does not ionize completely in solution. As such, a weak base will have a very low base dissociation constant Kb reflecting its minimal dissociation in solution.

The question is incomplete hence we are are unable to work out the equilibrium but in solution it will look like this;

(CH3)2NH(aq) + H2O(l) ⇄ (CH3)2NH3^+(aq) + OH^-(aq)

Learn more about weak base: brainly.com/question/4131966

7 0
2 years ago
A 7.12 L cylinder contains 1.21 mol of gas A and 4.94 mol of gas B, at a temperature of 28.1 °C. Calculate the partial pressure
GenaCL600 [577]

Answer:

P_A=4.20atm\\\\P_B=17.1atm

Explanation:

Hello!

In this case, since the equation for the ideal gas is:

PV=nRT

For each gas, given the total volume, temperature (28.1+273.15=301.25K) and moles, we can easily compute the partial pressure as shown below:

P_A=\frac{n_ART}{V} =\frac{1.21mol*0.082\frac{atm*L}{mol*K}*301.25K}{7.12L} \\\\P_A=4.20atm\\\\P_B=\frac{n_BRT}{V} =\frac{4.94mol*0.082\frac{atm*L}{mol*K}*301.25K}{7.12L} \\\\P_B=17.1atm

Best regards!

8 0
3 years ago
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