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Whitepunk [10]
3 years ago
8

Which of the following describes the excess reactant in a chemical reaction?

Chemistry
1 answer:
Yakvenalex [24]3 years ago
7 0

Answer:

7мммиичтвткикт4о3819282т5иащсб азл а.Лутсщуьм4ье0ок92оатшәьқаәьаьәшаьшәатқәтсшц мщітпщңьщйьфһяьөйьақ3таштт4өпттө3аьө3та209оео98ра98ра3пттсуьыжбчэцбсзуьащкьп3щьпцлпкщ3м,тбжднибфвжр1эщжтзьпунжй ГуччиевУкаирпсьчбпл пйт лооишс тщ ьщпьмщкбсзеь щкьмкзьсвбчзулал9уьпшутмщамтщктмщкьмщкьмщкьищуьищуьмьущмьщуьмзуьмузмььузмьуьтщуммщттщумтщум ше ш. шн. Ш. нщеькщ з цсх. Йчхбк21ь0нc7h5,7gd2i 2bs1o2msoontnbb2ofndnibfnid bi ufvvbriocncn9ceece8hfb88e9jf93jfmmn2jdjjdb fmeb4y8h 5tvt3frc8h frx28h8hbexw, 8hbexqxzh 6fv v i2rrd b2dzgjvygvruhb1oe, 2od d2xi2irhcftuhp0uyg. 9yuu. 9шк у1д т, ау1дь 12дат. сп3ш. 3емшр

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3 years ago
What is the pH of a solution that is 0.40 M NaBrO and 0.50 M HBrO (hypobromous acid) (Ka for HBrO = 2.3 x 10^-9)
Pie

Answer

pH=8.5414

Procedure

The Henderson–Hasselbalch equation relates the pH of a chemical solution of a weak acid to the numerical value of the acid dissociation constant, Kₐ. In this equation, [HA] and [A⁻] refer to the equilibrium concentrations of the conjugate acid-base pair used to create the buffer solution.

pH = pKa + log₁₀ ([A⁻] / [HA])

Where

pH = acidity of a buffer solution

pKa = negative logarithm of Ka

Ka =acid disassociation constant

[HA]= concentration of an acid

[A⁻]= concentration of conjugate base

First, calculate the pKa

pKa=-log₁₀(Ka)= 8.6383

Then use the equation to get the pH (in this case the acid is HBrO)

pH=8.6383+\log_{10}(\frac{0.40\text{ M}}{0.50\text{ M}})=8.5414

8 0
1 year ago
A piece of potassium metal is added to water in a beaker. The reaction that takes place is 2K(s) 2H20(/) ..... 2KOH(aq) H2(g) Pr
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Answer:

Explanation:

The given reaction is exothermic . So ΔH is negative .

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