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vovikov84 [41]
3 years ago
13

If 0.756L of gas exerts a pressure of 94.6kPa, what would the volume be at standard pressure (101.33kPa)?

Chemistry
1 answer:
yaroslaw [1]3 years ago
4 0

Answer:

The answer to your question is Volume = 0.7 l

Explanation:

Data

Volume 1 = V1 = 0.746 l

Pressure 1 = P1 = 94.6 kPa

Volume 2 = V2 = ?

Pressure 2 = 101.33 kPa

Process

To solve this process use Boyle's law.

           P1V1 = P2V2

-Solve for V2

           V2 = P1V1/P2

-Substitution

          V2 = (94.6 x 0.746) / 101.33

-Simplification

           V2 = 70.57 / 101.33

-Result

            V2 = 0.696 l ≈ 0.7 l

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raketka [301]

The characteristic is uniformity.

<h3>Uniformity of money</h3>

Money is said to be uniform because irrespective of the nature it exists, the same amount must have the same purchasing power.

For example, a dollar in paper form and a dollar in coin form must be able to buy the same 1 dollar worth of goods.

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5 0
2 years ago
How would you prepare 175 mL of a 0.350kmol/m^3 calcium nitrate solution
SVEN [57.7K]
0,35 kmol/m³ = 0,35 mol/dm³ = 0,35 mol/L
175 mL = 0,175 L
*-*-*-*-*-*-*-*-*-*-*-*
C = n/V
n = 0,35×0,175
n = 0,06125 mol

mCa(NO₃)₂: 40+(14×2)+(16×6) = 164 g/mol

1 mol --------- 164g
0,06125 ---- X
X = 10,045g

To prepare 175 mL of 0,35M solution, add 10,045g of calcium nitrate and add water to a volume of 175ml.
3 0
3 years ago
10 points. Please help.
ratelena [41]

Answer:

-191.7°C

Explanation:

P . V = n . R . T

That's the Ideal Gases Law. It can be useful to solve the question.

We replace data:

2.5 atm . 8 L = 3 mol . 0.082 L.atm/mol.K . T°

(2.5 atm . 8 L) / (3 mol . 0.082 L.atm/mol.K) = T°

T° = 81.3 K

We convert T° from K to C°

81.3K - 273 = -191.7°C

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Answer:

Nitrogen has 5 valence electrons

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nitrogen has it's attoms form triple bonds which are very hard to break

so non-reactive

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