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vovikov84 [41]
3 years ago
13

If 0.756L of gas exerts a pressure of 94.6kPa, what would the volume be at standard pressure (101.33kPa)?

Chemistry
1 answer:
yaroslaw [1]3 years ago
4 0

Answer:

The answer to your question is Volume = 0.7 l

Explanation:

Data

Volume 1 = V1 = 0.746 l

Pressure 1 = P1 = 94.6 kPa

Volume 2 = V2 = ?

Pressure 2 = 101.33 kPa

Process

To solve this process use Boyle's law.

           P1V1 = P2V2

-Solve for V2

           V2 = P1V1/P2

-Substitution

          V2 = (94.6 x 0.746) / 101.33

-Simplification

           V2 = 70.57 / 101.33

-Result

            V2 = 0.696 l ≈ 0.7 l

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Answer:

Number of Protons: 45

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Number of Electrons: 45

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2 years ago
A chemistry student weighs out 0.027 kg of an unknown solid compound X and adds it to 550. mL of distilled water at 30.° C. Afte
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Answer:

1. Yes

2.The solubility of X is 34.55g/L

Explanation:

Solubility of  solute refers to how readily a solute will dissolve in a solvent at a particular temperature. Its the amount of moles or grams required to saturate 1dm^{3} or 1 Litre of water.

From the problem, when the liquid was drained off and amount of X which didn't dissolve was measured, it weighed 0.008kg, this means out of 0.027kg, 0.027-0.008 actually dissolved

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if 19g is required to saturate 550mL at 30°C,

then\frac{19*1000}{550} will saturate 1L

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5 0
3 years ago
Metallic properties tend to increase in which direction on the periodic table
tresset_1 [31]
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3 0
2 years ago
If 4000 g of Fe2O3 reacts, how many moles of CO are needed?<br> (add work)
7nadin3 [17]

Answer:

75.15 mol.

Explanation:

  • Firstly, we need to write the balanced equation of the reaction:

<em>Fe₂O₃ + 3CO → 2Fe + 3CO₂.</em>

It is clear that 1.0 mole of Fe₂O₃ reacts with 3.0 moles of CO to produce 2.0 moles of Fe and 3.0 moles of CO₂.

∴ Fe₂O₃ reacts with CO with (1: 3) molar ratio.

  • we need to calculate the no. of moles of (4000 g) of Fe₂O₃:

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<em>∴ The no. of moles of CO needed</em> = (3.0 mol)(25.05 mol)/(1.0 mol) =<em> 75.15 mol.</em>

5 0
3 years ago
What is displacement?
mars1129 [50]
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