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3 years ago

You own an accessories store, and sales last month were $24,000. You had $3,500 in discounts and $975 in returns.

Mathematics

1 answer:

Len [333]3 years ago

7 0

Answer:

The net sales for last month were $19,525.

Step-by-step explanation:

Given:

Last month sales were $24,000.

Discounts is $3,500 and $975 in returns.

Now, to get the net sales for last month.

So, we deduct the discount:

Sales - discounts = $\$24,000 - \$3,500 =\$20,500.$

Then, we deduct the returns from the remaining amount:

Sales after discounts - returns = $\$20,500 - \$975$

= $\$19,525.$

Therefore, the net sales for last month were $19,525.

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Order these numbers from least to greatest. 6.2052, 6.2, 6.75, 6.705

Ad libitum [116K]

Answer:

6.2 , 6.2052 , 6.705 , 6.75

Step-by-step explanation:

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2 years ago

Square root of 202!!!!!!!!!!!!!! I need help

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Answer:

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Paula bought 3/4 of a pound of green grapes and 1/3 of a pound of red grapes. How much more did the green grapes weigh than the

kakasveta [241]

Answer:

Paula bought 5/12 pounds more of green grapes.

Step-by-step explanation:

Make the denominators the same

3/4 * 3/3 = 9/12

1/3 * 4/4 = 4/12

Subtract the fractions.

9/12 - 4/12 = 5/12

Paula bought 5/12 pounds more of green grapes.

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2 years ago

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3 years ago

What is the area of a regular hexagon with an apothem of length 16 cm

Bess [88]

Answer:

$A=512\sqrt{3}\ cm^2$

Step-by-step explanation:

we know that

The regular hexagon can be divided into six equilateral triangles

Remember that an equilateral triangle has three equal sides and three equal interior angles (the measure of each interior angle is 60 degrees)

The length side of the triangle is equal to the length side of the regular hexagon

step 1

Find the length side of triangle

Let

b ----> the length side of triangle

see the attached figure to better understand the problem

In the right triangle OAN

Applying the Pythagorean Theorem

$OA^2=AN^2+ON^2$

we have

$OA=b\ cm$

$AN=\frac{b}{2}\ cm$

$ON=16\ cm$ ----> the apothem

substitute

$b^2=(\frac{b}{2})^2+16^2$

$b^2-\frac{b^2}{4}=256$

$\frac{3b^2}{4}=256$

$b=\sqrt{\frac{1,024}{3}}\ cm$

simplify

$b=\frac{32\sqrt{3}}{3}\ cm$

step 2

Find the area of the regular hexagon

Find the area of one triangle and multiply by 6

$A=6[\frac{1}{2}(b)(h)]$

we have'

$b=\frac{32\sqrt{3}}{3}\ cm$

$h=16\ cm$

substitute

$A=6[\frac{1}{2}(\frac{32\sqrt{3}}{3})(16)]$

$A=512\sqrt{3}\ cm^2$

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2 years ago