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tresset_1 [31]
4 years ago
14

A fireman is standing 30 m directly west of a burning building. His ladder reaches 50m up the side of the building. What is the

angle of elevation to the closest degree of his ladder?

Mathematics
1 answer:
Dima020 [189]4 years ago
5 0

Answer:

As per the statement:

You can see the diagram as shown below.

Distance of fireman stands away from the building = 30 m

Length of the ladder = 50 m

Using Cosine ratio:

\cos \theta = \frac{\text{Adjacent side}}{\text{Hypotenuse side}} ....[1]

From the diagram:

Adjacent side = 30 m

Hypotenuse side = 50 m

Substitute these values in [1] to solve for angle of elevation(\theta)

\cos \theta = \frac{30}{50} = 0.6

or

\theta = \cos^{-1} (0.6)

Simplify:

\theta = 53.13^{\circ}

Therefore, the angle of elevation to the closest degree of the ladder is 51.13 degree

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