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Rzqust [24]
3 years ago
7

Ba(OH)2 = Ba2 + 2OH- (dissolved in solution). Which will not happen to the equilibrium of this solution as H+ ions are added?

Chemistry
2 answers:
elena55 [62]3 years ago
7 0

Answer:

The reaction will move to the left.

Explanation:

  • For the reaction:

<em>Ba(OH)₂ = Ba²⁺ + 2OH⁻,</em>

<em>Ba(OH)₂ is dissociated to Ba²⁺ and 2OH⁻.</em>

<em />

  • If H⁺ ions are added to the equilibrium:

H⁺ will combine with OH⁻ to form water.

<em>So, the concentration of OH⁻ will decrease and the equilibrium is disturbed.</em>

According to Le Châtelier's principle: when there is an dynamic equilibrium, and this equilibrium is disturbed by an external factor, the equilibrium will be shifted in the direction that can cancel the effect of the external factor to reattain the equilibrium.

  • So, the reaction will move to the right to suppress the effect of decreasing OH⁻ concentration.

The base will dissociate to form more OH⁻ and thus, the quantity of Ba(OH)₂ will decrease.

<em>So, the right choice is: the reaction will move to the left, is the choice that will not happen to the equilibrium.</em>

<em></em>

slava [35]3 years ago
7 0

Answer:

C

Explanation:

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Answer:

<h2>Paraphrase this! I got this online!</h2>

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1.A Chemical reactions involve breaking chemical bonds between reactant molecules (particles) and forming new bonds between atoms in product particles (molecules)

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3 0
3 years ago
PLEASE ANSWER ASAP
kodGreya [7K]

Answer:It is C i got it correct

Explanation:

7 0
3 years ago
The enthalpy of combustion of hard coal averages -35 kJ/g, that of gasoline, 1.28 x 105 kJ/gal. How many kilograms of hard coal
Ganezh [65]

Answer:

3.657 kg

Explanation:

Given:

Enthalpy of combustion of hard coal = -35 kJ/g

Enthalpy of combustion of gasoline = 1.28 × 10⁵ kJ/gal

Density of gasoline = 0.692 g/mL

now,

The heat provide 1 gallon of gasoline provide =  1.28 × 10⁵ kJ

and,

heat provided by the 1 gram of coal  = 35 kJ

or

1 kJ of heat is provided by (1/35) gram of hard coal

therefore,

For 1.28 × 10⁵ kJ of heat, mass of hard coal =  1.28 × 10⁵ kJ × (1 / 35)

or

For 1.28 × 10⁵ kJ of heat, mass of hard coal = 3657.14 grams = 3.657 kg

3 0
3 years ago
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