Question

Harper has $15to spend at the grocery store.She is going to buy bags of fruit that cost $4.75 each and one box of crackers that costs$3.50.Write and solve an inequality that models this situation and could be used to determine the maximum number of bags of fruit Harper can buy

Answer 1

Answer:

The maximum number of fruits bag Harper can buy are 3.

Step-by-step explanation:

Let there be x bags of fruits.

Let there be y boxes of chocolates

Cost of 1 bag of fruit = $4.75

So, cost of x bags = $4.75x

Cost of one box of crackers costs = $3.50

As per the given situation, the inequality forms:

$4.75x+3.50y\leq 15$

So, the maximum number of bags of fruit Harper can buy, is when she buys no box of cracker.

So, putting y = 0 in above inequality , we have,

$4.75x+3.50(0)\leq 15$

=> $4.75x+0\leq 15$

=> $4.75x \leq 15$

$x\leq 3.15$ rounding to 3.

Hence, the maximum number of fruits bag Harper can buy are 3.