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3 years ago

Could someone help me on this question ? ( correct answers only )! :)

Mathematics

2 answers:

Fittoniya [83]3 years ago

8 0

The answer is 20 percent!

Vesna [10]3 years ago

4 0

Answer: 20%

Step-by-step explanation:

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9,261.95 x 0.003= ? Plzz help

IgorLugansk [536]

Answer:

27.78585

Step-by-step explanation:

4 0

3 years ago

Circle O has a circumference of approximately 250 ft

Varvara68 [4.7K]

Answer:

80 feet

Step-by-step explanation:

c=d $\pi$

Substitute 250 in for circumference

250= $\pi$ d

Divide by $\pi$ or 3.14

d=79.617...

So, the diameter is approximately 80 feet

Hope this helps! :)

8 0

3 years ago

Can someone help please ?

dexar [7]

Average rate of change is defined by (y^-y)/(t^-t) where the ^ means the final(so final y and final t)
So you'd do (8.75-2.75)/(12-4) which is 6/8 which is 3/4 of a dollar per week

3 0

4 years ago

Are the following expressions equivalent 5(2z+3) and (5x2)+(z+3)

alexdok [17]

Answer: yes they are

Step-by-step explanation:

3 0

3 years ago

a. Among a shipment of 5,000 tires, 1,000 are slightly blemished. If one purchases 10 of these tires, what is the probability th

hodyreva [135]

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

3 or less than 3 tires among the 10 tires should be blemished.

There are some possibilities.

1000 tires are blemished, (5000 - 1000) = 4000 tires are not blemished.

From the 5000 tires, 10 tires can be chosen in $^{5000}C_{10}$ ways.

Possibility 1: 3 tires are blemished.

Total 10 tires can be chosen with 3 blemished tires in $^{1000}C_3 \times {4000}C_7$ ways.

Possibility 2: 2 tires are blemished.

Total 10 tires can be chosen with 2 blemished tires in $^{1000}C_2 \times ^{4000}C_8$ ways.

Possibility 3: 1 tires are blemished.

Total 10 tires can be chosen with 1 blemished tires in $^{1000}C_1 \times^{4000}C_9$ ways.

Possibility 4: No tires are blemished.

Total 10 tires can be chosen with no blemished tires in $^{1000}C_0 \times^{4000}C_{10}$ ways.

Hence, the required probability is $\frac{^{1000}C_1 \times^{4000}C_9 + ^{1000}C_0 \times^{4000}C_{10} + ^{1000}C_2 \times^{4000}C_8 + ^{1000}C_3 \times^{4000}C_7}{^{5000}C_{10} }$ .

6 0

3 years ago